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steposvetlana [31]
1 year ago
15

Northern Hemisphere winters are colder than Northern Hemisphere summers because Northern Hemisphere winters are colder than Nort

hern Hemisphere summers because a) Earth is closer to the sun during the summer than it is during the winter. b) the snow that falls in the northern latitudes cools Earth during the winter. c) the light from the sun shines more directly on the Northern Hemisphere during the summer. d) the period of sunlight is longer during the summer than during the winter. e) both c) and d) above are correct
Geography
1 answer:
antoniya [11.8K]1 year ago
4 0

Answer:

e) both c) and d) above are correct

Explanation:

The equator is an imaginary line running from east to west that divides the earth into the northern hemisphere and southern hemisphere. The northern hemisphere is the half part of the earth that is north of the equator.

During the summer, the light from the sun shines more directly on the Northern Hemisphere.

Also during summer, the period of sunlight is longer than that of the winter.

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Halite and gypsum. Minerals that crystallize from the seawater are the example of hydrogenous sediment .
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The hypotenuse of right triangle ABC, line segment AC, measures 13 cm. The length of line segment BC is 5 cm. What is the approx
ipn [44]

Answer:  44.8\°

Explanation:

We have a right triangle with sides AB, BC=5cm and AC=13cm (the hypotenuse). Let's apply the Pithagorean Theorem to find AB:

AC^{2}=AB^{2} + BC^{2}  (1)

AB^{2}=AC^{2} - BC^{2} (2)

AB^{2}=(13cm)^{2} - (5cm)^{2} (3)

AB=12cm (4)

Now that we know the value of each side of the triangle, we will use the trigonometric function sine to find the angles C and A (angle B is 90\° remembering we are talking about a right triangle):

For angle C:

sinC=\frac{Oppositeside}{Hypotenuse}

sinC=\frac{12}{13}  (5)

C=sin^{-1}(\frac{12}{13})  (6)

C=67.38\°  (7)

For angle A:

sinA=\frac{5}{13}  (8)

A=sin^{-1}(\frac{5}{13})  (9)

A=22.62\°  (10)

Calculating the difference between both angles:

C-A=67.38\°- 22.62\°

C-A=44.76\° \approx 44.8\°

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2 years ago
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Identify each statement as either true or false.
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1.false

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5. How fast did the shoes travel? (4 points) a. From where the shoes spilled (48°N, 161°W) to where they first made landfall (49
Leto [7]

Answer:

a) d = 35.0143 Km

t = 188 days

v = 7.76*10⁻³ Km/h

b) d = 28.6356 Km

t = 2165 days

v = 5.51*10-4 Km/h

Explanation:

a. From where the shoes spilled (48°N, 161°W) to where they first made landfall (49°N, 126°W), how many kilometers did they travel?  

We can use the equation

d = √(∆N²+∆W²)

⇒   d = √((49-48)²+(126-161)²) = 35.0143 Km

How many days did they take to travel that distance? (You can use November 30 as the date found).  

From May 27, 1990 to November 30, 1990 we have

t = 5 days + (30 days/month)*(3 months) + (31 days/month)*(3 months) = 188 days

⇒   t = 188 days = (188 days)*(24 hours/day) = 4512 hours

What was their rate of travel in kilometers per hour?  

We use the equation

v = d/t   ⇒   v =  35.0143 Km/ 4512 h

⇒   v = 7.76*10⁻³ Km/h

b. From where the shoes spilled (48°N, 161°W) to where they were found in 1996 (54°N, 133°W), how many kilometers did they travel?  

We can use the equation

d = √(∆N²+∆W²)

⇒   d = √((54-48)²+(133-161)²) = 28.6356 Km

How many days did they take to travel that distance (use April 30 as the date found)?  

From May 27, 1990 to April 30, 1996 we have

t = 5 days + (30 days/month)*(4 months) + (31 days/month)*(6 months) + 29 days + (365 days/ year)*(4 years)+ (366 days/ year)*(1 year)= 2165 days

⇒   t = 2165 days = (2165 days)*(24 hours/day) = 51960 hours

What was their rate of travel in kilometers per hour?

We use the equation

v = d/t   ⇒   v =  28.6356 Km/ 51960 h

⇒   v = 5.51*10-4 Km/h

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I think you can identify it by pulling a line from the north pole and see which cities are crossed with one another
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One example would be New york City and Buffalo

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