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Nataly_w [17]
1 year ago
8

You are responsible for a rail convoy of goods consisting of several boxcars. You start the train and after a few minutes you re

alize that some boxcars are overloaded and weigh too heavily on the rails while others are dangerously light. So you decide to stop the train and spread the weight more evenly so that all the boxcars have exactly the same weight (without changing the total weight). For that you write a program which helps you in the distribution of the weight.
Your program should first read the number of cars to be weighed (integer) followed by the weights of the cars (doubles). Then your program should calculate and display how much weight to add or subtract from each car such that every car has the same weight. The total weight of all of the cars should not change. These additions and subtractions of weights should be displayed with one decimal place. You may assume that there are no more than 50 boxcars.
Example 1
In this example, there are 5 boxcars with different weights summing to 110.0. The ouput shows that we are modifying all the boxcars so that they each carry a weight of 22.0 (which makes a total of 110.0 for the entire train). So we remove 18.0 for the first boxcar, we add 10.0 for the second, we add 2.0 for the third, etc.
Input
5
40.0
12.0
20.0
5. 33.
0
Output
- 18.0
10.0
2.0
17.0
-11.0
Computers and Technology
1 answer:
maks197457 [2]1 year ago
4 0

Answer:

The program in C++ is as follows:

#include <iostream>

#include <iomanip>

using namespace std;

int main(){

   int cars;

   cin>>cars;

   double weights[cars];

   double total = 0;

   for(int i = 0; i<cars;i++){

       cin>>weights[i];

       total+=weights[i];    }

   double avg = total/cars;

   for(int i = 0; i<cars;i++){

       cout<<fixed<<setprecision(1)<<avg-weights[i]<<endl;    }

   return 0;

}

Explanation:

This declares the number of cars as integers

   int cars;

This gets input for the number of cars

   cin>>cars;

This declares the weight of the cars as an array of double datatype

   double weights[cars];

This initializes the total weights to 0

   double total = 0;

This iterates through the number of cars

   for(int i = 0; i<cars;i++){

This gets input for each weight

       cin>>weights[i];

This adds up the total weight

       total+=weights[i];    }

This calculates the average weights

   double avg = total/cars;

This iterates through the number of cars

   for(int i = 0; i<cars;i++){

This prints how much weight to be added or subtracted

       cout<<fixed<<setprecision(1)<<avg-weights[i]<<endl;    }

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3.14 LAB: Simple statistics for Python
Ad libitum [116K]

Answer:

Following are the correct python code to this question:

n1 = float(input('Input first number: '))#input first number  

n2 = float(input('Input second number: '))#input second number  

n3 = float(input('Input third number: '))#input third number  

n4 = float(input('Input fourth number: '))#input fourth number  

average = (n1+n2+n3+n4)/4 #calculate input number average

product = n1*n2*n3*n4 # calculate input number product

print('product: {:.0f}  average: {:.0f}'.format(round(product),round(average))) #print product and average using round function

print('product: {:.3f}  average: {:.3f}'.format(product,average)) #print product and average value

Output:

Please find the attachment.

Explanation:

The description of the above python code can be defined as follows:

  • In the above python program four variable "n1, n2, n3, and n4" is defined, in which we take input from the user end, and in these user inputs we use the float method, that converts all the input value in to float value.
  • In the next step, two variable average and product are defined, that calculate all input numbers product, average, and hold value in its variable.
  • In the last line, the print method is used, which prints its variable value by using a round and format method.

8 0
2 years ago
Given a int variable named yesCount and another int variable named noCount and an int variable named response write the necessar
sergejj [24]

// This command takes input from the user.

Scanner input = new Scanner(System.in);

int response= input.nextInt();

// Making the variables required

int noCount =0 ;

int yesCount =0;

// Checking the response if it is 1 or 2 and reporting accordingly

if(response == 1 || response ==2){

 yesCount+=1;

 System.out.println("YES WAS RECORDED");

}

// Checking if the input is 3 or 4 then printing the required lines

else if (response == 3 || response ==4){

noCount+=1;

 System.out.println("NO WAS RECORDED");

}

// if the input is not valid than printing INVALID

else{

System.out.println("INVALID");

}

 

 

 

6 0
2 years ago
Write the 8-bit signed-magnitude, two's complement, and ones' complement representations for each decimal number: +25, + 120, +
pshichka [43]

Answer:

Let's convert the decimals into signed 8-bit binary numbers.

As we need to find the 8-bit magnitude, so write the powers at each bit.

      <u>Sign -bit</u> <u>64</u> <u>32</u> <u>16</u> <u>8</u> <u>4</u> <u>2</u> <u>1</u>

+25 - 0 0 0 1 1 0 0 1

+120- 0 1 1 1 1 0 0 0

+82 - 0 1 0 1 0 0 1       0

-42 - 1 0 1 0 1 0 1 0

-111 - 1 1 1 0 1 1 1 1

One’s Complements:  

+25 (00011001) – 11100110

+120(01111000) - 10000111

+82(01010010) - 10101101

-42(10101010) - 01010101

-111(11101111)- 00010000

Two’s Complements:  

+25 (00011001) – 11100110+1 = 11100111

+120(01111000) – 10000111+1 = 10001000

+82(01010010) – 10101101+1= 10101110

-42(10101010) – 01010101+1= 01010110

-111(11101111)- 00010000+1= 00010001

Explanation:

To find the 8-bit signed magnitude follow this process:

For +120

  • put 0 at Sign-bit as there is plus sign before 120.
  • Put 1 at the largest power of 2 near to 120 and less than 120, so put 1 at 64.
  • Subtract 64 from 120, i.e. 120-64 = 56.
  • Then put 1 at 32, as it is the nearest power of 2 of 56. Then 56-32=24.
  • Then put 1 at 16 and 24-16 = 8.
  • Now put 1 at 8. 8-8 = 0, so put 0 at all rest places.

To find one’s complement of a number 00011001, find 11111111 – 00011001 or put 0 in place each 1 and 1 in place of each 0., i.e., 11100110.

Now to find Two’s complement of a number, just do binary addition of the number with 1.

6 0
2 years ago
Splunk In most production environments, _______ will be used as the source of data input?
Wittaler [7]

Answer: Forwarders

Explanation:

Splunk is defined as the software technology which helps in organization of applications, examining and monitoring of the data and information analytics.It performs the operation of indexing, processing and gathering to produce graphs, alert ,report etc .

  • Forwarders are the component of Splunk software that gathers the information and transmit it to the Splunk clod for further analysis and processing .It is considered as the reliable method for input of data.

6 0
1 year ago
Complete the function to replace any period by an exclamation point. Ex: "Hello. I'm Miley. Nice to meet you." becomes:
vodomira [7]

Answer:

Here is the complete function:

void MakeSentenceExcited(char* sentenceText) {  // function that takes the text as parameter and replaces any period by an exclamation point in that text

int size = strlen(sentenceText);  //returns the length of sentenceText string and assigns it to size variable

char * ptr;  // character type pointer ptr

ptr = sentenceText;  // ptr points to the sentenceText string

for (int i=0; i<size; i++){  //iterates through the sentenceText string using i as an index

    if (sentenceText[i]=='.'){  // if the character at i-th index of sentenceText is a period

        sentenceText[i]='!'; } } } //places exclamation mark when it finds a period at i-th index of sentenceText

Explanation:

The program works as follows:

Suppose we have the string:

sentenceText = "Hello. I'm Miley. Nice to meet you."

The MakeSentenceExcited method takes this sentenceText as parameter

int size = strlen(sentenceText) this returns the length of sentenceText

The size of sentenceText is 35 as this string contains 35 characters

size =  35

Then a pointer ptr is declared which is set to point to sentenceText

for (int i=0; i<size; i++) loop works as follows:    

1st iteration:

i=0

i<size is true because i=0 and size = 35 so 0<35

So the body of loop executes:

 if (sentenceText[i]=='.') statement checks :

if (sentenceText[0]=='.')

The first element of sentenceText is H

H is not a period sign so the statement inside if statement does not execute and value of i increments to 1. Now i = 1

2nd iteration:

i=1

i<size is true because i=1 and size = 35 so 1<35

So the body of loop executes:

 if (sentenceText[i]=='.') statement checks :

if (sentenceText[1]=='.')

This is the second element of sentenceText i.e. e

e is not a period sign so the statement inside if statement does not execute and value of i increments to 1. Now i = 2

So at each iteration the if condition checks if the character at i-th index of string sentenceText is a period.

Now lets see a case where the element at i-th index is a period:

6th iteration:

i=5

i<size is true because i=5 and size = 35 so 5<35

So the body of loop executes:

 if (sentenceText[i]=='.') statement checks :

if (sentenceText[5]=='.')

This is the character at 5th index of sentenceText i.e. "."

So the if condition evaluates to true and the statement inside if part executes:

sentenceText[i]='!'; statement becomes:

sentenceText[5]='!'; this means that the character at 5th position of sentenceText string is assigned an exclamation mark.

So from above 6 iterations the result is:

Hello!

This loop continues to execute until all the characters of sentenceText are checked and when the value of i gets greater than or equal to the length of sentenceText then the loop breaks.

The screenshot of the program along with its output is attached.

6 0
1 year ago
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