Is it possible that<br> 1952<br> is the remainder of 375139654

The nth term of a sequence is 2n2 − 1 The nth term of a different sequence is 40 − n2 Show that there is only one number that is

allsm [11]

Answer:

Step-by-step explanation:

nth term of a sequence = 2n² - 1

Therefore, terms of the sequence will be,

1, 7, 17, 31, 49, ........... n terms

nth term of a different sequence = 40 - n²

Therefore, terms of the sequence will be,

39, 36, 31, 24, 15, 4, -9, -24 .......... n terms

Since, there is no negative number in the first sequence,

Therefore, out of 6 positive terms of second sequence only one number (31) is common in both the sequences.

5 0

2 years ago

1. A person owns a collection of 30 CDs, of which 5 are country music. If 2 CDs are selected at

OverLord2011 [107]

Answer:

Step-by-step explanation:

Sunflower can u please come answer my question next it says

HELP ASAP WILL GIVE BRAINLIEST PLEASE IM DESPERATE!!!!!!!

5 0

1 year ago

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Emiyo has used 2 1/4 gallons of paint.This is 2/3 of the total amount of paint.How much ,p, did Emiyo have to start?

Leni [432]

Answer:

3 3/8

Step-by-step explanation:

y×(2/3)=2.25 (the same as 2 1/4)

÷2/3. ÷2/3

y=3.375

3 3=8 gallons

more of break down:

y×2/3=9/4

÷2/3 or ×3/2

y= 9. 3. 27

--- × ---- = ----- = 3 3/8

4. 2. 8

6 0

1 year ago

The following exercise refers to choosing two cards from a thoroughly shuffled deck. Assume that the deck is shuffled after a ca

dem82 [27]

Answer:

$\frac{4}{663}$

Step-by-step explanation:

Given that from a well shuffled set of playing cards (52 in number) a card is drawn and without replacing it, next card is drawn.

A - the first card is 4

B - second card is ace

We have to find probability for

$A\bigcap B$

P(A) = no of 4s in the deck/total cards = $\frac{4}{52} =\frac{1}{13}$

After this first drawn if 4 is drawn, we have remaining 51 cards with 4 aces in it

P(B) = no of Aces in 51 cards/51 = $\frac{4}{51}$

Hence

$P(A\bigcap B) = \frac{1}{13} *\frac{4}{51} \\=\frac{4}{663}$

(Here we see that A and B are independent once we adjust the number of cards. Also for both we multiply the probabilities)

8 0

1 year ago

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Mr. Woo wants to ship a fishing rod to his son that is 42 inches long. He has a box that measures 10 inches by 10 inches by 40 i

chubhunter [2.5K]

Answer:

The 42 inches long fishing rod will fit in the box.

Step-by-step explanation:

The diagonal of a cuboidal box is the largest measurement inside the box.

Now, the dimensions of the box are 10 inches by 10 inches by 40 inches.

Therefore, the diagonal length of the box is $\sqrt{10^{2} + 10^{2} + 40^{2}} = 42.42$ inches which is greater than 42 inches.

Hence, the 42 inches long fishing rod will fit in the box. (Answer)

8 0

2 years ago

Is it possible that 1952 is the remainder of 375139654 - 1953?