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irinina [24]
2 years ago
8

Server Corporation is a majority-owned subsidiary of Proxy Corporation. Proxy acquired 75 percent ownership on January 1, 20X3,

for $133,500. At that date, Server reported common stock outstanding of $60,000 and retained earnings of $90,000, and the fair value of the noncontrolling interest was $44,500. The differential is assigned to equipment, which had a fair value $28,000 more than book value and a remaining economic life of seven years at the date of the business combination. Server reported net income of $30,000 and paid dividends of $12,000 in 20X3.
Required:
a. Give the journal entries recorded by West during 20X3 on its books if it accounts for its investment in Canton using the equity method.
b. Give the eliminating entries needed at December 31, 20X3, to prepare consolidated financial statements.
Business
1 answer:
kirill115 [55]2 years ago
7 0

Answer:

1/1/2013

Dr Investment in server corporation $133,500

Cr Cash $133,500

1/1/2013

Dr Investment in server corporation $22,500

Cr Cash $22,500

1/1/2013

Dr Cash $9000

Cr Investment in server corporation $9000

1/1/2013

Dr Investment in server corporation $3000

Cr Investment income from serverbcorporation $3000

Explanation:

Preparation of the journal entries

1/1/2013

Dr Investment in server corporation $133,500

Cr Cash $133,500

(To record cash invested)

1/1/2013

Dr Investment in server corporation $22,500

($30,000*75/100)

Cr Cash $22,500

( To record cash invested according to net income)

1/1/2013

Dr Cash $9000

Cr Investment in server corporation $9000

( To record cash received)

1/1/2013

Dr Investment in server corporation $3000

Cr Investment income from serverbcorporation $3000

( To record cash recieved from income)

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tamaranim1 [39]

Answer and Explanation:

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6 0
2 years ago
The manager of a major retail store has taken a random sample of 25 customers. The average sale was $52.50. The population stand
Anna35 [415]

Answer:P value = 1 - 0.9793 = 0.0207

Explanation:

we can use Z value and normal distribution to find P value. P value is the area of beyond the value of Z value

sample mean (x.bar) = $52.20

Population mean (U) = $50

Sample Standard deviation (Sd) =$ 6.10

sample (n) = 25

Z =\frac{(x.bar - U)}{Sd/\sqrt{n} } =\frac{52.50 - 50}{6.10/\sqrt{25} }

Z = 2.50/1.22 = 2.049280328 = 2.049

area (normal distribution table) = 0.9793

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7 0
2 years ago
When Nina tells her manager that she doesn't feel she needs to attend various training sessions at company expense or utilize su
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Answer:

The right answer is, False.

Explanation:

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2 years ago
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<u>Answer:</u>

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<em></em>

<u>Explanation:</u>

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4 0
2 years ago
Read 2 more answers
1. A time study analyst timed an assembly operation for 30 cycles, and then computed the average time per cycle, which was 18.75
WARRIOR [948]

Answer:

1. observed time = 18.75 minutes.

2. Normal time = 18 minutes

3. Standard time = 21.17 minutes

Explanation:

1. The observed time will be equal to the average time per cycle, which was given in the question as 18.75 min. Therefore, observed time = 18.75 minutes.

2. The normal time will be:

= Average Time x Performance Rating

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3. The standard time will be:

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= 18 × 1/0.85

= 18 × 1.176

= 21.17 minutes

5 0
2 years ago
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