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mart [117]
1 year ago
7

a ball pushed with a force of 13.5 n accelerates at 6.5 m/s2 to the right. what is the mass of the ball?

SAT
1 answer:
denis23 [38]1 year ago
7 0

Answer:

Explanation:

the equation you use here is m=fa or mass=force x acceleration

you plug in the 13.5 N as the force, 6.5 m/s^2 as the acceleration, and do the math.

13.5 x 6.5

That would equal 87.75 which would be your answer.

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Answer:

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Explanation:

When the dough is folded, it increases by a constant factor. We can model the growth of the thickness using the exponential growth model

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We want to find the smallest number of times Soon Yi will have to roll and fold the dough so that the resulting dough is at least 2.5mm.

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2(1+0.08)^n\geq 2.5\\2(1.08)^n\geq 2.5\\$Divide both sides by 2$\\\dfrac{2(1.08)^n}{2}\geq \dfrac{2.5}{2}\\\\1.08^n\geq 1.25\\\\$Change to logarithm form\\n \geq \log_{1.08}1.25\\\\n\geq \dfrac{\log 1.25}{\log 1.08} \\\\n\geq 2.9

Therefore, the smallest number of times Soon Yi will have to roll and fold the dough so that the resulting dough is at least 2.5mm thick is 3.

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