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sashaice [31]
2 years ago
5

In the box, complete the first 4 steps for graphing the quadratic function given. (Use ^ on the keyboard to indicate an exponent

.) Then print a sheet of graph paper and graph the quadratic function to turn in to your teacher. Be sure to label the axes and vertex.
y = -x 2 - 4x - 3
Mathematics
1 answer:
Vaselesa [24]2 years ago
7 0
Step 1: convert the equation into fhe vertex form

To do you can complete squares:

y = - [x^2 + 4x + 3]

y = - [ (x + 2)^2 - 4 + 3]

y = - [ (x + 2)^2 - 1] = - (x+2)^2 + 1

Then the vertex is (-2, 1)

Now you can drasw the vertex


Step 2: Find the roots (zeros)

y = - [ (x + 2)^2 - 1] = 0

(x + 2)^2 - 1 = 0

(x+2)^2 = 1

(x+2) = (+/-) √1

x + 2 = (+/-1)

x = - 2 +/- 1

x = -1 and x = -3

Now you draw the points (-1,0) , (-3,0)

Step 3: find the interception with the y-axis.

That is y value when x = 0

y = - (0)^2 - 4(0) - 3 = -3

Then draw the point (0, -3)

Step 4: given that the coefficent of x is negative (-1) the parabola is open downward.

So, with those four points: vertex (-2,1), (-1,0), (-3,0) and (0,-3), you can sketch the function.
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Mason is tiling the floor of his bathroom, which measures 9.75 feet by 8.63 feet. He estimates the area. Will he have enough til
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He will have more than enough because he only needs to cover 84.1425 square feet.
3 0
2 years ago
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On a number​ line, the coordinates of​ X, Y,​ Z, and W are ​, ​, ​, and ​, respectively. Find the lengths of the two segments be
Arturiano [62]

Complete Question:

On a number​ line, the coordinates of​ X, Y,​ Z, and W are −8​, −5​, 4​, and 6​, respectively. Find the lengths of the two segments below. Then tell whether they are congruent. \overline{XY} and \overline{ZW}

Answer:

\overline{XY} = 3

\overline{ZW} = 2

They are not congruent

Step-by-step explanation:

Length of segment XY:

Coordinate of X = -8

Coordinate of Y = -5

\overline{XY} = |-8 -(-5)| = |-8 + 5| = 3

Length of ZW:

Coordinate of Z = 4

Coordinate of W = 6

\overline{ZW} = |4 - 6| = 2

\overline{XY} ≠ \overline{ZW}, therefore, they are not congruent.

3 0
2 years ago
Solve the compound inequality. Graph the solution set.<br> -2x&lt;2x-4&lt;4
Arte-miy333 [17]
I hope this helps you

-2x <2x-4

4 <4x

1 <x

2x-4 <4

2x <8

x <4

1 <x <4
5 0
2 years ago
Divide rs 350 in ratio 2:5​
mihalych1998 [28]

Answer:

100 : 250

Step-by-step explanation:

Sum the parts of the ratio, 2 + 5 = 7 parts

Divide the quantity by 7 to find the value of one part of the ratio.

350 ÷ 7 = 50 ← value of 1 part of the ratio, thus

2 parts = 2 × 50 = 100

5 parts = 5 × 50 = 250

350 = 100 : 250 in the ratio 2 : 5

6 0
2 years ago
In parallelogram ABCD , diagonals AC⎯⎯⎯⎯⎯ and BD⎯⎯⎯⎯⎯ intersect at point E, AE=x2−16 , and CE=6x .
MAXImum [283]

Answer:

<h3>AC=96 units.</h3>

Step-by-step explanation:

We are given a parallelogram ABCD with diagonals AC and BD intersect at point E.

AE=x^2-16. , and CE=6x .

<em>Note: The diagonals of a parallelogram intersects at mid-point.</em>

Therefore, AE = EC.

Plugging expressions for AE and EC, we get

x^2-16=6x.

Subtracting 6x from both sides, we get

x^2-16-6x=6x-6x

x^2-6x-16=0

Factoriong quadratic by product sum rule.

We need to find the factors of -16 that add upto -6.

-16 has factors -8 and +2 that add upto -6.

Therefore, factor of x^2-6x-16=0 quadratic is (x-8)(x+2)=0

Setting each factor equal to 0 and solve for x.

x-8=0  => x=8

x+2=0  => x=-2.

We can't take x=-2 as it's a negative number.

Therefore, plugging x=8 in EC =6x, we get

EC = 6(8) = 48.

<h3>AC = AE + EC = 48+48 =96 units.</h3>
5 0
2 years ago
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