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2 years ago

7

A classroom measures 12 meters long and 9 meters wide. When using a scale of 1 cm to 1.5 m to draw the room on your paper, the s

ize would be

1 answer:

Tema [17]2 years ago

6 0

12m(cm/1.5m) by 9m(cm/1.5m)

8cm by 6cm

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A video game requires at least 4 points to advance. Each solved puzzle is worth two points. Each solved riddle is worth 1 point.

Gwar [14]

Answer:

The graph in the attached figure

Step-by-step explanation:

Let

x -----> the number of solved puzzles

y -----> the number of solved riddles

we know that

$2x+y \geq 4$

The solution of the inequality is the shaded area above the solid line $2x+y=4$

The slope of the solid line is negative $m=-2$

The y-intercept of the solid line is the point (0,4)

The x-intercept of the solid line is the point (2,0)

therefore

The graph in the attached figure

3 0

2 years ago

Read 2 more answers

In the morning, Marco sold 12 cups of lemonade for $3. By the end of the day, he had earned $9. How many cups of lemonade did he

MA_775_DIABLO [31]

Answer:

Marco earned $2.25.

Step-by-step explanation:

1. If Marco sold 12 cups of lemonade for 3$, we would divide 12 cups and how much he earned from the 12 cups (3$). 12/3 = 4

2. By the end of the day, Marco earned $9. So, 4 cups = 1$. To break it down, 1$ = 100 cents and 100 cents divided by 4 is 25 cents. Cups to Cost. ( 4 : 1 ) and/or ( 1 : 0.25 )

3. 8 cups = 2$ plus 1 cup (0.25) = 2.25.

~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~

7 0

2 years ago

Read 2 more answers

Colin invests £2350 into a savings account. The bank gives 4.2% compound interest for the first 4 years and 4.9% thereafter. How

mixer [17]

To solve this, we are going to use the compound interest formula: $A=P(1+ \frac{r}{n} )^{nt}$
where
$A$ is the final amount after $t$ years
$P$ is the initial investment
$r$ is the interest rate in decimal form
$n$ is the number of times the interest is compounded per year

For the first 4 years we know that: $P=2350$ , $r= \frac{4.2}{100} =0.042$ , $t=4$ , and since the problem is not specifying how often the interest is communed, we are going to assume it is compounded annually; therefore, $n=1$ . Lest replace those values in our formula:
$A=P(1+ \frac{r}{n} )^{nt}$
$A=2350(1+ \frac{0.042}{1} )^{(1)(4)}$
$A=2350(1+0.042)^{4}$
$A=2770.38$

Now, for the next 6 years the intial investment will be the final amount from our previous step, so $P=2770.38$ . We also know that: $r= \frac{4.9}{100} =0.049$ , $t=6$ , and $n=1$ . Lets replace those values in our formula one more time:
$A=P(1+ \frac{r}{n} )^{nt}$
$A=2770.38(1+ \frac{0.049}{1})^{(1)(6)$
$A=2770.38(1+0.049)^6$
$A=3691.41$

We can conclude that Collin will have <span>£3691.41 in his account after 10 years.</span>

4 0

2 years ago

(a) Find a vector-parametric equation r⃗ 1(t)=⟨x(t),y(t),z(t)⟩r→1(t)=⟨x(t),y(t),z(t)⟩ for the shadow of the circular cylinder x2

motikmotik

Answer: (a) r1(t) = <2cost , 0 , 2sint>

(b) <2cost , (1 - 12sint - 10cost)/8 , 2sint>

Step-by-step explanation:

x2+z2=4

a)

Now, in the xz plane, we know that y = 0...

So, x^2 + z^2 = 4 will simply be a circle centered at (0,0)..

This can be easily parameterized as

x = 2cos(t)

z = 2sin(t)

So, the required parameterization is :

r1(t) = <2cost , 0 , 2sint>

b)

Cylinder : x^2 + z^2 = 4

Plane : 5x+8y+6z=1

Easily enough, the x^2 + z^2 = 4 can again be parameterized as

x = 2cost , z = 2sint

With this, we can find y using plane equation...

5x+8y+6z=1

5(2cost) + 8y + 6(2sint) = 1

8y = 1 - 12sint - 10cost

y = (1 - 12sint - 10cost)/8

So, the parameterization is :

<2cost , (1 - 12sint - 10cost)/8 , 2sint>

6 0

2 years ago

Membership to a racket ball club has an application fee and a monthly fee that can be modeled by the function c(m) = 12.50m + 49

Ghella [55]

Answer: the last one

Step-by-step explanation:

6 0

2 years ago