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TiliK225 [7]
2 years ago
7

Sphere A has a radius of 24 centimeters, and sphere B has a diameter of 42 centimeters. The radius of sphere A is multiplied by

what factor to produce the radius of sphere B?
4/7
7/8
8/7
7/4
Mathematics
2 answers:
Tamiku [17]2 years ago
5 0

Answer:

7/8

Step-by-step explanation:

Sphere A has a radius of 24 centimeters, and sphere B has a diameter of 42 centimeters.

WE need find which factor is multiplied with radius of sphere A to produce the radius of sphere B

Diameter of sphere B is 42

Radius = diameter /2

Radius = 42/2= 21

Radius of sphere B = 21

RAdius of sphere A times x= radius of sphere B

24 * x= 21

Divide by 24 on both sides

x= 21/ 24

divide top and bottom by 3

x= 7/ 8

Gwar [14]2 years ago
3 0

Answer: The factor is 7/8

Step-by-step explanation:

Ok, we know that Sphere A as a radius of 24 cm, and sphere B has a diameter of 42 cm.

We want to find the factor which multiplied by the radius of sphere A gives us the radius of sphere B.

First, let's find the radius of sphere B.

We know that Diameter = 2*Radius.

So the radius of sphere B is equal to the diamater divided by 2.

rB = 42cm/2 = 21cm

now, let's find the number x that:

24cm*x = 21cm

x= 21cm/24cm = 21/24  

now, we can divide numerator and denominator by the same number, in this case 3, and get:

x = 21/24 = (21/3)/(24/3) = 7/8

x = 7/8

So the factor is x= 7/8, the second option.

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Answer:

a) 42°F < x < 176°F

b) The inequality graph is attached.

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Step-by-step explanation:

According to the Question,

a) For the benzene to remain in liquid form, the temperature of benzene must be less than the boiling point and greater than the boiling point. Let x be the temperature of benzene, For benzene to remain as liquid, its temperature must be between:

42°F < x < 176°F

b) The inequality graph is attached. The graph shows that the temperature of benzene must be between 42°F and 176°F so that it would be a liquid. The Closed circles represent that it is greater than 2.

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Evaluate the line integral by the two following methods. xy dx + x2y3 dy C is counterclockwise around the triangle with vertices
nadezda [96]

Answer:

a)

\frac{2}{3}

b)

\frac{2}{3}

Step-by-step explanation:

a) The first part requires that we use line integral to evaluate directly.

The line integral is

\int_C xydx +  {x}^{2}  {y}^{3} dy

where C is counterclockwise around the triangle with vertices (0, 0), (1, 0), and (1, 2)

The boundary of integration is shown in the attachment.

Our first line integral is

L_1 = \int_ {(0,0)}^{(1,0)} xydx +  {x}^{2}  {y}^{3} dy

The equation of this line is y=0, x varies from 0 to 1.

When we substitute y=0 every becomes zero.

\therefore \: L_1 =0

Our second line integral is

L_2 = \int_ {(1,0)}^{(1,2)} xydx +  {x}^{2}  {y}^{3} dy

The equation of this line is:

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We substitute the boundary and the values to get:

L_2 = \int_ {1}^{2}1 \cdot y(0) +  {1}^{2}   \cdot \: {y}^{3} dy

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The 3rd line integral is:

L_3 = \int_ {(1,2)}^{(0,0)} xydx +  {x}^{2}  {y}^{3} dy

The equation of this line is

y = 2x \implies \: dy = 2dx

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We substitute to get:

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L_3 = \int_ {1}^{0} 8 {x}^{5}  + 2 {x}^{2} dx  =  - 2

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L = L_1 + L_2 + L_3

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b) The second part requires the use of Green's Theorem to evaluate:

\int_C xydx +  {x}^{2}  {y}^{3} dy

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\int_C \: xydx + {x}^{2} {y}^{3}   \: dy =  \int_ 0^{1} \:  8{x}^{5} -  2 {x}^{2}   dx =  \frac{2}{3}

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2 years ago
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anastassius [24]
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