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galina1969 [7]
2 years ago
11

Which statement shows how two polynomials 4x + 6 and 2x2 − 8x demonstrate the closure property when multiplied?

Mathematics
2 answers:
Sholpan [36]2 years ago
8 0
In order to multiply out two polynomials, we can us FOIL, which stands for First, Outer, Inner, Last. First, we multiply the first terms of the polynomials together, then the outer terms, etc. This gives us 8x^3 - 32x^2 + 12x^2 - 48x. By combining like terms, we can then get 8x^3 - 20x^2 - 48x. This term is a polynomial because it has more than 2 terms (it has 4). Therefore, the answer is A. 8x^3 - 20x^2 - 48x is a polynomial.

Hope this helps!
steposvetlana [31]2 years ago
7 0

Answer:

8x^{3} -20x^{2} -48x is a polynomial

Step-by-step explanation:

Given : polynomials 4x+6 and2x^{2} -8x

Solution:

(4x+6)*(2x^{2} -8x)

4x(2x^{2} -8x)+6(2x^{2} -8x)

8x^{3} -32x^{2}+12x^{2} -48x

8x^{3} -20x^{2} -48x

Polynomial :An expression of more than two algebraic terms, especially the sum of several terms that contain different powers of the same variable.

Thus 8x^{3} -20x^{2} -48x is a polynomial

Hence option A is correct.




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Ibrahim has some building blocks that are all cubes of the same size. He uses three of the blocks to make a pile with a height o
MArishka [77]

Answer:

72.5

Step-by-step explanation:

one block = 43.5 / 3 = 14.5

five blocks = 5 * 14.5 = 72.5 (ans)

4 0
2 years ago
Explain why the following expression is false. |x| < -4
levacccp [35]

Step-by-step explanation:

Whenever we put a negative number inside a modulus function it will give us the positive output. For example , |-3| = 3 , |-6|=6, |5|= 5 ,etc.

So a modulus function i.e. |x| is always greater than zero ( positive ) when x is any number except 0 and it is equal to zero when the value of x is 0.

So |x| can't be less than -4 as |x| is always positive . So the statement is false.

8 0
2 years ago
100/225 square feet of your bakery will be used as your storefront, where customers come visit. The rest kill be used for storag
Lelu [443]
The answer is 5/9. I showed a bit more work on the other post
7 0
2 years ago
A circular platform is to be built in a playground. The center of the structure is required to be equidistant from three support
castortr0y [4]

Answer:

The coordinates for the location of the center of the platform are (0, 1)

Step-by-step explanation:

The equation of the circle of center (h , k) and radius r is:

(x - h)² + (y - k)² = r²

Now,

- The center is equidistant from any point lies on the circumference of the circle

- There are three points equidistant from the center of the circle

- We have three unknowns in the equation of the circle h , k , r

Thus, let's substitute the coordinates of these point in the equation of the circle to find h , k , r.

The equation of the circle is (x - h)² + (y - k)² = r²

∵ Points A(2,−3), B(4,3), and C(−2,5)

- Substitute the values of x and y the coordinates of these points

Point A (2 , -3)

(2 - h)² + (-3 - k)² = r² - - - (1)

Point B (4 , 3)

(4 - h)² + (3 - k)² = r² - - - - (2)

Point C (-2 , 5)

(-2 - h)² + (5 - k)² = r² - - - - (3)

- To find h , k equate equation (1) and (2) and same for equation (2) and (3) because all of them equal r²

Thus;

(2 - h)² + (-3 - k)² = (4 - h)² + (3 - k)² - - - - - (4)

(4 - h)² + (3 - k)² = (-2 - h)² + (5 - k)² - - - - -(5)

- Simplify (5);

h² - 8h + 16 + k² - 6k + 9 = h² + 4h + 4 + k² - 10k + 25

h² and k² will cancel out to give;

-8h - 6k + 25 = 4h - 10k + 29

Rearranging, we have;

12h - 4k = -4 - - - - (6)

Similarly, for equation 4;

(2 - h)² + (-3 - k)² = (4 - h)² + (3 - k)²

h² - 4h + 4 + k² + 6k + 9 = h² - 8h + 16 + k² - 6k + 9

h², k² and 9 will cancel out to give;

4 - 4h + 6k = 16 - 8h - 6k

Rearranging;

4h + 12k = 12 - - - - (7)

Divide by 4 to give;

h + 3k = 3

Making h the subject;

h = 3 - 3k

Put 3 - 3k for h in eq 6;

12(3 - 3k) - 4k = -4

36 - 36k - 4k = -4

40k = 40

k = 40/40

k = 1

h = 3 - 3(1)

h = 0

The coordinates for the location of the center of the platform are (0, 1)

5 0
2 years ago
Find the solution set of the following equations: <br><br>2y=2x+7<br><br>X=y+2
kirill115 [55]

Answer:

The system of equations has no solution.

Step-by-step explanation:

Given the system of equations

2y = 2x+7

x = y+2

solving the system of equations

\begin{bmatrix}2y=2x+7\\ x=y+2\end{bmatrix}

Arrange equation variables for elimination

\begin{bmatrix}2y-2x=7\\ -y+x=2\end{bmatrix}

Multiply -y+x=2 by 2:  -2y+2x=4

\begin{bmatrix}2y-2x=7\\ -2y+2x=4\end{bmatrix}

so adding

-2y+2x=4

+

\underline{2y-2x=7}

0=11

so the system of equations becomes

\begin{bmatrix}2y-2x=7\\ 0=11\end{bmatrix}

0 = 11 is false, therefore the system of equations has no solution.

Thus,

No Solution!

3 0
2 years ago
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