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2 years ago

Which statement shows how two polynomials 4x + 6 and 2x2 − 8x demonstrate the closure property when multiplied?

2 answers:

8 0

In order to multiply out two polynomials, we can us FOIL, which stands for First, Outer, Inner, Last. First, we multiply the first terms of the polynomials together, then the outer terms, etc. This gives us 8x^3 - 32x^2 + 12x^2 - 48x. By combining like terms, we can then get 8x^3 - 20x^2 - 48x. This term is a polynomial because it has more than 2 terms (it has 4). Therefore, the answer is A. 8x^3 - 20x^2 - 48x is a polynomial.

Hope this helps!

steposvetlana [31]2 years ago

7 0

Answer:

$8x^{3} -20x^{2} -48x$ is a polynomial

Step-by-step explanation:

Given : polynomials $4x+6$ and $2x^{2} -8x$

Solution:

$(4x+6)*(2x^{2} -8x)$

$4x(2x^{2} -8x)+6(2x^{2} -8x)$

$8x^{3} -32x^{2}+12x^{2} -48x$

$8x^{3} -20x^{2} -48x$

Polynomial :An expression of more than two algebraic terms, especially the sum of several terms that contain different powers of the same variable.

Thus $8x^{3} -20x^{2} -48x$ is a polynomial

Hence option A is correct.

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There are S steps from the pedestal to the head of the Statue of Liberty.The number of steps in the Washington Monument is 27 le

ozzi

w=Washington monument steps

w= 27-6s so the expression is w= 6s-27

The one with the variable always goes first.

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Hope this helps, now you know the answer and how to do it. HAVE A BLESSED AND WONDERFUL DAY! As well as a great rest of Black History Month! :-)

- Cutiepatutie ☺❀❤

4 0

2 years ago

give an example of an addition problem in which you would and would not group the addends differently to add

Montano1993 [528]

If you're adding positive numbers together, then the order in which you write or group the addends doesn't matter.

If you're "adding" a negative number to a positive number, it's a little easier to visualize this problem if you write the positive number first, followed by the negative number.

But if you're "adding" -15 to 8, it'd make sense to write the -15 first (because its magnitude is greater) and then the 8: -15 + 8 = -7

4 0

2 years ago

The quality control manager at a light bulb factory needs to estimate the mean life of a batch (population) of light bulbs. We a

Nadusha1986 [10]

Answer:

a)95% confidence intervals for the population mean of light bulbs in this batch

(325.5 ,374.5)

The calculated value Z = 4 > 1.96 at 0.05 level of significance

Null hypothesis is rejected

The manufacturer has not right to take the average life of the light bulbs is 400 hours.

Step-by-step explanation:

Given sample size n = 64

Given mean of the sample x⁻ = 350

Standard deviation of the Population σ = 100 hours

The tabulated value Z₀.₉₅ = 1.96

95% confidence intervals for the population mean of light bulbs in this batch

$(x^{-} - Z_{\frac{\alpha }{2} } \frac{S.D}{\sqrt{n} } , x^{-} + Z_{\frac{\alpha }{2} }\frac{S.D}{\sqrt{n} } )$

$(350 - 1.96\frac{100}{\sqrt{64} } , 350 + 1.96\frac{100}{\sqrt{64} } )$

$(350 -24.5, 350 +24.5)$

(325.5 ,374.5)

Explanation:-

Given mean of the Population μ = 400

Given sample size n = 64

Given mean of the sample x⁻ = 350

Standard deviation of the Population σ = 100 hours

Null hypothesis : H₀:The manufacturer has right to take the average life of the light bulbs is 400 hours.

μ = 400

Alternative Hypothesis: H₁: μ ≠400

The test statistic

$Z = \frac{x^{-}-mean }{\frac{S.D}{\sqrt{n} } }$

$Z = \frac{350 -400}{\frac{100}{\sqrt{64} } }$

|Z| = |-4|

The tabulated value Z₀.₉₅ = 1.96

The calculated value Z = 4 > 1.96 at 0.05 level of significance

Null hypothesis is rejected.

Conclusion:-

The manufacturer has not right to take the average life of the light bulbs is 400 hours.

5 0

2 years ago

Antonio and Candice had a race. Their distances past a particular landmark as the race progressed can be represented by linear f

Luda [366]

I got the answer Antonio had a head start of 3 meters.

4 0

1 year ago

Three trigonometric functions for a given angle are shown below. cosecant theta = thirteen-twelfths; secant theta = Negative thi

Kay [80]

Answer:

(–5, 12) is the correct answer.

Step-by-step explanation:

We are given the following values:

$cosec\theta = \dfrac{13}{12}\\sec\theta=-\dfrac{13}{5}\\cot\theta =-\dfrac{5}{12}$

Now, we know the following identities:

$sin \theta = \dfrac{1}{cosec\theta}\\cos \theta = \dfrac{1}{sec\theta}\\tan \theta = \dfrac{1}{cot\theta}$

Now, the values are:

$sin\theta = \dfrac{12}{13}\\cos\theta=-\dfrac{5}{13}\\tan\theta =-\dfrac{12}{5}$

Sine value is positive and cos, tan values are negative.

It can be clearly observed that $\theta$ is in 2nd quadrant.

2nd quadrant means, the value of $x$ will be negative and $y$ will be positive.

Let us have a look at the value of $tan\theta$ :

$tan\theta = \dfrac{Perpendicular}{Base}\\OR\\tan\theta = \dfrac{y-coordinate}{x-coordinate} = -\dfrac{12}{5}\\\therefore y = 12,\\x = -5$

Please refer to the attached image for clear understanding and detailed explanation.

Hence, the correct answer is coordinate (x,y) is (–5, 12)

8 0

2 years ago