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geniusboy [140]
2 years ago
3

Jason and Jenny are out on a lunch date. Jason gives Jenny a bouquet that has 4 roses, 3 carnations, and 4 orchids. They decide

that Jenny gets to choose their lunch order if the flower she randomly picks from the bouquet is a carnation or a rose. What is the probability that Jenny gets to choose lunch?
Mathematics
2 answers:
uranmaximum [27]2 years ago
6 0
4 + 3 + 4 = 11
There are 7 flowers that Jenny can pick in order to order lunch.
Therefore the probability is 7/11
Kisachek [45]2 years ago
3 0
7/11.......................
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In the diagram shown of circle A, tangent MB is drawn along with chords BAC and BF . Secant MFE intersects BAC at G. It is known
mote1985 [20]

Answer:

  • arc BF = 76°
  • ∠M = 31°
  • ∠BGE = 121°
  • ∠MFB = 111°

Step-by-step explanation:

(a) ∠FBM is the complement of ∠FBC, so is ...

  ∠FBM = 90° -52° = 38°

The measure of arc BF is twice this angle, so is ...

  arc BF = 2∠FBM = 2(38°)

  arc BF = 76°

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(b) ∠M is half the difference between the measures of arcs BE and BF, so is ...

  ∠M = (1/2)(138° -76°) = 62°/2

  ∠M = 31°

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(c) arc FC is the supplement to arc BF, so has measure ...

  arc FC = 180° -arc BF = 180° -76° = 104°

∠BGE is half the sum of arcs BE and FC, so is ...

  ∠BGE = (1/2)(arc BE +arc FC) = (138° +104°)/2

  ∠BGE = 121°

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(d) ∠MFB is the remaining angle in ∆MFB, so has measure ...

  ∠MFB = 180° -∠M -∠FBM = 180° -31° -38°

  ∠MFB = 111°

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The Hazell family has 4 children. Murphy is 1 year younger than his older brother Michael. Keira is 2 years younger than Murphy.
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Assume that the national average score on a standardized test is 1010, and the standard deviation is 200, where scores are norma
kotykmax [81]

Answer:

0.00

Step-by-step explanation:

If the national average score on a standardized test is 1010, and the standard deviation is 200, where scores are normally distributed, to calculate the probability that a test taker scores at least 1600 on the test, we should first to calculate the z-score related to 1600. This z-score is z=\frac{1600-1010}{200}=2.95, then, we are seeking P(Z > 2.95), where Z is normally distributed with mean 0 and standard deviation 1. Therefore, P(Z > 2.95) = 0.00

4 0
2 years ago
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Archimedes (ca. 287-212 B.C.) was able to use clever geometric means to determine the relative volumes of a cylinder and the con
VLD [36.1K]

Answer:

The ration of the volume of  cone to that of   cylinder is   \frac{V_{cone}}{V_{cy}} = \frac{1}{3}  

Step-by-step explanation:

From the question we are told that

 The volume of a cone is mathematically represented as

        V_{cone} = \frac{1}{3} \pi r^2 h

The volume of a cylinder is mathematically represented as

       V_{cy} = \pi r^2 h

Now the ratio we are to obtain is

          \frac{V_{cone}}{V_{cy}}  = \frac{\frac{1}{3}  \pi r^2 h}{\pi r^2 h}    

                   \frac{V_{cone}}{V_{cy}} = \frac{\frac{1}{3} }{1}         Note: this is possible because the height and base

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6 0
2 years ago
A veterinarian's office recorded one particular week that they had 50 patients. The following table shows the recorded number of
Gre4nikov [31]

Answer:

1. <u>The correct answer is 46%</u>

2. <u>The correct answer is .07</u>

<u>3. The correct answer is (34%,58%)</u>

4. <u>The correct answer is (32%,60%)</u>

Step-by-step explanation:

1. Let's calculate the percentage or proportion of patients that were dogs:

p = (7 + 4 + 5 + 5 + 2)/50 = 23/50 = 0.46

<u>The correct answer is 46%</u>

2. Let's estimate the standard error, using the given formula, this way:

S.e = √ (0.46 * 0.54)/50 = √0.049 = 0.07

<u>The correct answer is .07</u>

<u>3. </u>Let's calculate the confidence limits of the 90% confidence interval, this way:

Confidence limits = proportion +/- 1.645 * standard error

Confidence limits = 0.46 +/- 1.645 * 0.07

Confidence limits = 0.46 +/- 0.12

Confidence limits = 0.34, 0.58

<u>The correct answer is (34%,58%)</u>

4. <u> </u>Let's calculate the confidence limits of the 95% confidence interval, this way:

Confidence limits = proportion +/- 1.96 * standard error

Confidence limits = 0.46 +/- 1.96 * 0.07

Confidence limits = 0.46 +/- 0.14

Confidence limits = 0.32, 0.60

<u>The correct answer is (32%,60%)</u>

3 0
2 years ago
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