I assume that in this item, we are asked to solve for the force exerted during the heartbeat. Force is the product of the mass and acceleration. To solve for the acceleration in this item, we divide the velocity by time.
a = 1 m/s / 0.2 s = 5 m/s²
Then, we multiply this by the mass (in kg)
F = (80 g / 1000 g/kg) x (5 m/s²)
= 0.4 kg m/s² = 0.4 J
Therefore, every hearbeat will take 0.4 J of force.
4^3 = 64
There are 64 ways to arrange the four bases (Adenine, Thymine, Cytosine, and Guanine) into triplets (include repeats of bases as well, for e.g. AAT).
Just in case you are confused by my use of Thymine above, one thing to note is that Thymine will be replaced with Uracil in RNA.
Hope this helps! :)
Answer: Fungus like protists are heterotrophic and feed on organic matter.
Cellular slime mould is a species of fungus like protists that form slug.
Explanation:
Fungus like protists are heterotrophic and the feed on organic matter and mostly unicellular.
Cellular slime mould are protists belonging to class Dictyostelia. They are heterotrophic and decomposers that live on organic matter. When there is deterioration condition, the cells migrates together to form slugs and move to form new habitat. Some of the cells form stalk and others form spores.
The correct term to fill in the blank would be intensity. The intensity of exercise determines whether carbohydrates or fat is the predominant source of energy production. During high-intensity workouts, it is the fat that is used as the source of energy production while low-intensity exercises would only use the carbohydrates present for energy.
Answer:
25% or 1/4
Explanation:
The gene for colour in Heliodors is controlled by two contrasting alleles that codes for Red (R) and Yellow (Y) colours. However, these two alleles exhibit incomplete dominance, which is a phenomenon whereby a combination of both alleles gives rise to a third intermediate phenotype that is a blending of the other two parental phenotypes. In this case, both colours gives rise to a heterozygous Orange coloration (RY) in Heliodors.
However, if two orange Heliodors (RY) are crossed, four possible offsprings will be produced with the genotypes: RR, RY, RY, YY. This shows a phenotypic ratio of 1 red: 2orange: 1yellow. Hence, the probability of having a child with red coloration is 1 out of 4 possible offsprings i.e. 1/4.
Expressing this in percentage, we have 1/4 × 100 = 25%.
