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Sunny_sXe [5.5K]
2 years ago
15

12-5x-4kx=y solve for x

Mathematics
1 answer:
GalinKa [24]2 years ago
7 0
12-5x-4kx=y :x 

-5x-4kx=y-12 

-x(5+4k)=y-12 

-x= \dfrac{y-12}{5+4k} 

x=- \dfrac{y-12}{5+4k}
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Let's denote students in D = in the drama club , S<span> = in a sports team </span>
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P(neither D nor S) = 1- 15/22 </span><span>= 7/22</span>
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We now find the absolute value of the distance of each value from the mean.

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{5.5,1.5,11.5,5.5,3.5,3.5,5.5,7.5}

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The least absolute deviation is 1.5. This is not within one absolute deviation.

Therefore none of the data set is closer than one mean absolute deviation away from  the mean.

5 0
2 years ago
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2 years ago
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