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2 years ago

How many gallons of a 20% salt solution must be mixed with 4 gallons of a 30% salt solution to make a 25% salt solution?

1 answer:

6 0

Since 25% is smack in the middle between 20% and 30%, it will take equal volumes of ech to make a 25% solution.

Since 4 gallons of 30% solution was used, so 4 gallons of 20% solution will be needed.

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A pure acid measuring x liters is added to 300 liters of a 20% acidic solution. The concentration of acid, f(x), in the new subs

Natali5045456 [20]

Answer How many liters of a 20% acid solution should be mixed with 30 liters of 50% acid solution in order to obtain a 40% solution. ... x=15 liters 15*(.20 pure acid)=3 liters 30*(.50 pure acid)=15 liters That is 18 liters pure acid That is 45 liters solution *0.45 pure acid=18 liters.

As more pure acid is added, the concentration of acid approaches 0.

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2 years ago

Read 2 more answers

All students are classified as either full-time or part-time. Kenneth conducted a survey in which he collected data on the perce

Crank

Answer:

Step-by-step explanation:

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2 years ago

La hormiguita Fidencia se encontro una hojita, la cargo y se llevo al hormiguero. Le dio a su amiguita 1/5 y ella se comió 1/3 d

vredina [299]

Answer:

The ant Fidencia ate more

Step-by-step explanation:

The question in English

The ant Fidencia found a leaf, the charge and took the anthill. She gave her friend 1/5 and she ate 1/3 of the leaf. Who ate more?

Her friend

Multiply (1/5) by (3/3)

(1/5)*(3/3)=3/15

Ant Fidencia

Multiply (1/3) by (5/5)

(1/3)*(5/5)=5/15

Compare

5/15 > 3/15 -----> two fractions with the same denominator the fraction with the highest numerator is greater

therefore

The ant Fidencia ate more

7 0

2 years ago

What is the potential outlier in the following data set of populaion densities? 1,19,35,43,49,55,63,94,105,110,175,231,239,351,7

MAXImum [283]

Answer:

738

Step-by-step explanation:

It’s to different from the other numbers

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2 years ago

Convert decimal +49 and +29 to binary, using the signed‐2’s‐complement representation and enough digits to accommodate the numbe

Serhud [2]

To solve this problem, let us first find for the binary equivalents of the numbers. They are:

Decimal --> Binary

+ 29 --> 00011101

+ 49 --> 00110001

- 29 --> 11100011

- 49 --> 11001111

Now we apply the normal binary arithmetic to these converted numbers:

(+ 29) + (- 49) ---> 00011101 + 11001111 = 11101100 ---> - 20 (TRUE)

(- 29) + (+ 49) ---> 11100011 + 00110001 = 00010100 ---> + 20 (TRUE)

(- 29) + (- 49) ---> 11100011 + 11001111 = 10110010 ---> - 78 (TRUE)

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2 years ago