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KATRIN_1 [288]
2 years ago
15

Look at the body shapes of the fish shown below.

Biology
2 answers:
sergey [27]2 years ago
4 0

The correct answer is option B

The fishes that live in the shallow water along the sea floor needs a flattened shape and eyes on the dorsal side because they need to see above and have least possibility that the eyes will be required to see downwards as they lie at the sea floor.

They have tail for protection and flattened body for easy swimming.

Example: Stingray.

Hoochie [10]2 years ago
4 0
Im pretty sure its the flat fish 

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Determine whether the description applies to landfills, incinerators, or both
kompoz [17]

Answer:

Explanation:

1. can generate energy – Both , In landfills methane gas is produced which is used to generate electricity, like wise heat energy produced in incinerator is also used for producing energy

2. emits toxins through combustion – Incinerators produce dioxins which is a dangerous chemical

3. drains liquids into the ground – Land fill, leachate is a common issue with all landfill site.  

4. releases greenhouse gases – Both, methane and other carbon gases are produced in both landfill and incinerators

5. requires a substantial amount of land – land fill site , needs a large land to dump the city waste

6. generate ash – Incenerator only

4 0
2 years ago
A fly has two alleles for the color of its eyes. The green allele is recessive, and is represented by q. The blue allele is domi
murzikaleks [220]

Answer:

p = 0.34

Explanation:

The green allele is recessive, meaning two copies of q (qq) are required to be green. Conversely, animals that are either pp or pq will be blue.

If 44 organisms are green, that means 44 are qq.

For genotype frequencies, the equation is:

homozygous dominant genotype + heterozygous + homozygous recessive = 100%

Which is denoted as

p² + 2pq + q² = 1

We know that q² = 44/100 = 0.44

To work out q, we can do \sqrt{0.44} = 0.66

For allele frequencies, the total must add up to 100%, so

p + q =1

We know that q= 0.66

So p = 0.34, because 0.66 + 0.34 = 1

7 0
2 years ago
Messenger RNA carries a(n) ___________ of the DNA’s instructions out of the nucleus to the ___________.
Nitella [24]


messenger RNA  (mRNA) carries a transcript (copy) of the DNA's instructions out of the nucleus  to the cytoplasm where it attaches to a ribosome.

transfer RNA (tRNA) begins to read (translate) the information on the attached mRNA and corresponding to this information, fetches the appropriate amino acids from the pool of free amino acids in the cytoplasm, and brings them to the ribosome where they are linked into a chain or polymer forming the primary structure of the desired protein.

3 0
2 years ago
Read 2 more answers
I started out as magma down in the earths
erastovalidia [21]
Lava is the next step after magma if it reaches the surface 


8 0
2 years ago
Read 2 more answers
In mammoths, assume that spotted skin (S) is dominant over non-spotted skin (s) and that wooly hair (W) is dominant over non-woo
lisabon 2012 [21]

Answer:

Genotypic and Phenotypic ratios → 1:1:1:1

  • 25% of the progeny is expected to be SsWw, exhibiting spotted skin and wooly hair, SsWw
  • 25% of the progeny is expected to be Ssww, exhibiting spotted skin and non-wooly hair, Ssww
  • 25% of the progeny is expected to be ssWw, exhibiting non- spotted skin and wooly hair, ssWw
  • 25% of the progeny is expected to be ssww, exhibiting non-spotted skin and non-wooly hair, ssww

Explanation:

<u>Available data</u>:

  • spotted skin (S) is dominant over non-spotted skin (s)
  • wooly hair (W) is dominant over non-wooly hair (w)
  • Cross: heterozygous spotted, non-wooly mammoth with a heterozygous wooly-haired, non-spotted mammoth.

Parentals) Ssww   x   ssWw

Gametes) Sw, Sw, sw, sw

                 sW, sW, sw, sw

Punnett square)     Sw            Sw           sw           sw

                  sW      SsWw      SsWw      ssWw     ssWw

                  sW      SsWw      SsWw      ssWw     ssWw

                  sw      Ssww       Ssww       ssww      ssww

                  sw      Ssww       Ssww       ssww      ssww

F1) 4/16 = 1/4 = 25% of the progeny is expected to be SsWw, exhibiting spotted skin and wooly hair

    4/16 = 1/4 = 25% of the progeny is expected to be Ssww, exhibiting spotted skin and non-wooly hair

    4/16 = 1/4 = 25% of the progeny is expected to be ssWw, exhibiting non- spotted skin and wooly hair

    4/16 = 1/4 = 25% of the progeny is expected to be ssww, exhibiting non-spotted skin and non-wooly hair.

Genotypic and Phenotypic ratios → 1:1:1:1

7 0
2 years ago
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