Answer:
D.Competitive inhibition will decrease because the proportion of the active sites occupied by substrate will increase.
Explanation:
Methyl alcohol is a competitive inhibitor of ethyl alcohol. This means that both of them compete with each other for the same enzyme (ADH). Methyl alcohol leads to poisoning because it is converted to toxic formaldehyde in body. It can be treated by increasing the concentration of ethyl alcohol.
More ethyl alcohol (substrate) will reduce the competitive inhibition by methyl alcohol (inhibitor). This will happen because a substrate needs active sites on an enzyme to attach to it. If ethyl alcohol is increased in concentration, it will occupy more active sites and their availability to methyl alcohol will be reduced. Thus, the enzyme will not be able to act on methyl alcohol.
Evaluation of branding accenture compaigns
Although not specified, I am assuming that you want to identify the different variables and groups of this case. To answer this, the different typical factors that make up an experimental set up include: 1) dependent and 2) independent variables; 3) controlled variables; as well as the 4) control and 5) experimental group.
The dependent variable in this case is: the size of the population. While the independent variable is: the habitat space. Controlled variables in this experiment include: type and amount of food, cleanliness of the aquarium, and water temperature. The experimental group are simply the fish being observed. There are no controlled groups in this case depending on your definition. Controlled groups are usually the reference point or standard in experimental setups but this experiment wants to look at the differences of the goldfish with each other and not necessarily to a one particular goldfish and hence no controlled group.
The dependent variable is called as such because it is the one that changes depending on the factors given and is usually the one being observed. The independent variable is named as such because it remains the same throughout the experiment.
Active transport moves small molecules against the a concentration gradient which is the opposite of diffusion or that's what i found in Quizlet
