Question

Object E has a mass of 4,800 kilograms. Object F has a mass of 600 kilograms. Both objects were placed on different planets so that their weights are equal.
The gravity acting on Object E is ________ times the gravity acting on Object F.

A) 1⁄8

B) 1⁄4

C) 1

D) 8

Answer 1

The answer is 8 because 4800 divided by 600 equals 8 so the right answer is d

Answer 2

Answer:

Option A

Explanation:

Mass of object E $= 4,800$ kilogram

Mass of object E $= 600$ kilogram

Let the gravity of planet on which object E is placed $= g_{1}$

Gravity of planet on which object F is placed $= g_{2}$

As we know -

Weight is equal to the product of mass and gravity.

The weight of both the objects is same after they are placed on planets with different gravity.

$M_{E} * g_{1} = M_{F} * g_{2} \\\frac{M_{E}}{M_{F}} = \frac{g_{2}}{g_{1}}$

Substituting the given values in above equation, we get -

$\frac{4800}{600} = \frac{g_{2}}{g_{1}} \\\frac{g_{2}}{g_{1}} = 8$

Thus,  gravity acting on Object E is ___$\frac{1}{8}$_____ times the gravity acting on Object F.