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SashulF [63]
2 years ago
8

Object E has a mass of 4,800 kilograms. Object F has a mass of 600 kilograms. Both objects were placed on different planets so t

hat their weights are equal.
The gravity acting on Object E is ________ times the gravity acting on Object F.

A) 1⁄8

B) 1⁄4

C) 1

D) 8
Biology
2 answers:
3241004551 [841]2 years ago
7 0
The answer is 8 because 4800 divided by 600 equals 8 so the right answer is d
prohojiy [21]2 years ago
5 0

Answer:

Option A

Explanation:

Mass of object E = 4,800 kilogram

Mass of object E = 600 kilogram

Let the gravity of planet on which object E is placed = g_{1}

Gravity of planet on which object F is placed = g_{2}

As we know -

Weight is equal to the product of mass and gravity.

The weight of both the objects is same after they are placed on planets with different gravity.

M_{E} * g_{1} = M_{F} * g_{2} \\\frac{M_{E}}{M_{F}} = \frac{g_{2}}{g_{1}} \\

Substituting the given values in above equation, we get -

\frac{4800}{600} = \frac{g_{2}}{g_{1}} \\\frac{g_{2}}{g_{1}} = 8

Thus,  gravity acting on Object E is ___\frac{1}{8}_____ times the gravity acting on Object F.

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