Answer:
946.35mL (to 2 decimal places)
Explanation:
Use the formula
C1V1 = C2V2
where C1 is the concentration of the undiluted medication = 15mg/mL
V1 is the volume of the undiluted medication = 1 pint = 473.176mL (convert pint to mL)
C2 is the concentration that the diluted medication should have = 5mg/mL
V2 is the volume of the diluted medication with syrup = ??
C1V1 = C2V2
15mg/mL x 473.176mL = 5mg/mL x V2
<u>15mg/mL x 473.176mL = V2</u>
5mg/mL
1419.528mL = V2
V2 = 1419.528mL (expected volume of medication + syrup)
Therefore, amount of non-medicated flavored syrup base to be added = 1419.528mL - 473.176mL
= 946.352mL (2 pints)
Answer:
They could go on hikes!
Explanation:
Hiking or exploring their backyards together would be the perfect way to study plants and animals while also exercising.
a. A translation stop codon is added at the 3' end of the pre-mRNA.
c. A poly-A tail (50-250 adenine nucleotides) is added to the 3' end of the pre-mRNA.
d. Coding sequences called exons are spliced out by ribosomes.
Explanation:
In eukaryotes, during protein synthesis, the RNA must exit nucleus through the pores on the nuclear membrane and enter into the cytoplasm to undergo translation.
The exit processes of mRNA are: the 5’ capping, 3’ Poly-A tail, and pre-mRNA splicing.
The 5’capping is the initial step with addition of 7-methylguanosine cap to the 5’ end of the mRNA by phosphate linkage. This process protects the mRNA from degrading and helps to initiate translation processes.
The 3’ Poly-A tail step is the cleaving of pre-mRNA and addition of addition of around 200 A nucleotides or the 3’poly (A) tail to the mRNA by the poly (A) polymerase enzyme protein complex. This prevents pre-mRNA degradation, facilitates movement of mRNA to the cytoplasm, and initiates translation.
Pre-mRNA splicing is done to remove the introns from the mRNA because they are not part of function protein coding. The exons which take part in protein coding sequence are spliced once the introns are excised.
Finally, the resultant mRNA will exit the nucleus and enter the cytoplasm to undergo translation
.
Answer:
The sample was broken down by electric current and formed a new burnable substance The initial substance, then, is a compound.
