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Elza [17]
1 year ago
6

A group of high school students decide to hold a rally during school hours to protest cuts in the state's education budget. they

march through classrooms, recruiting students to join the rally. would the tinker standard support the students' expression of their opinions?
Business
2 answers:
DaniilM [7]1 year ago
8 0

Answer:

No.

Explanation:

The thinker standard was a ruling made in 1969  by the supreme court in the case Tinker vs Des Moines Independent Community School District, which started because 3 students used a black armband to the school as a protest on the Vietnam war, it states that students are allowed to express their own beliefs and their first amendment rightsas long as it doesn´t disrupt regular school activities, since this protest is stopping classes and interrupting normal school activities the Tinker standar wouldn´t support the students expressions of their opinions.

Vedmedyk [2.9K]1 year ago
7 0
No, because it disrupts school activities
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Instructions: Round your answers to 2 decimal places. If you are entering a negative number include a minus sign. a. Using the m
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Answer:

The answer is below

Explanation:

The graph is attached below.

a) The price elasticity of demand is given by:

price elasticity of demand = \frac{\%\ change\ in\ quantity }{\%\ change\ in\ price}=\frac{\Delta Q}{\Delta P}

\Delta Q=\frac{Q_2-Q_1}{(Q_2+Q_1)/2} \\\\\Delta P=\frac{P_2-P_1}{(P_2+P_1)/2}

Price of elasticity demand =   \frac{\frac{Q_2-Q_1}{(Q_2+Q_1)/2} }{\frac{P_2-P_1}{(P_2+P_1)/2} }

Price of elasticity demand =   \frac{\frac{50-100}{(50+100)/2} }{\frac{4.5-4}{(4.5+4.0)/2} }=\frac{-0.6667}{0.1176} =5.7

Since the price of elasticity demand > 1, it is elastic

b) Price of elasticity demand =   \frac{\frac{200-300}{(200+300)/2} }{\frac{3-2}{(3+2)/2} }=\frac{-0.4}{0.4} =1

Since the price of elasticity demand = 1, it is unitary

c) Price of elasticity demand =   \frac{\frac{400-450}{(400+450)/2} }{\frac{1-0.5}{(1+0.5)/2} }=\frac{-0.1176}{0.6667} =0.18

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The Acmeville Metropolitan Bus Service currently charges $0.88 for an all-day ticket and is used by an average of 513 riders a d
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= \frac{Q2 - Q1}{\frac{Q1 + Q2}{2} } \\\\= \frac{363 - 513}{\frac{513 + 363}{2} }\\\\= -0.342

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