They are probably looking for B. subscribing to journals is a good way of keeping up with what's happening in any field.
Of course, a very carefully curated professional network online is great for this too (but they said "personal" so that's not the answer)
Employers generally prefer that employees WORK as often as possible, so even though JUDICIOUS use of social media is a great way to keep current, D isn't the answer either.
Blogging about personal experiences is not necessarily going to teach you anything about work, though blogging professionally can be useful in gathering response from your readership
Answer:
consistent phrasing is missing
Explanation:
If you will note carefully, the bullets are not in correct format. The model is missing. The correct one is as below.
Risks
The correct form of presentation is as below:
1. Risks
a. employees
a. physical illness
b. mental illness
c. death
2. Customers
a. complaints
b. downtime
3. Benefits
However, the content seems to be complete now, and hence not anything else is required. And since its not something very tough to decide to go with, bite the bullet is certainly not an issue.
Answer:
- If a group of 9 kids have won a total of 100 trophies, then at least one of the 9 kids has won at least 12 trophies.
- If a person buys at least 400 cups of coffee in a year, then there is at least one day in which the person has bought at least two cups of coffee.
- The average of three real numbers is greater than or equal to at least one of the numbers.
Explanation:
1)
Suppose that each kid has less than 12 trophies
Total trophies = 100
Maximum trophies won by one kid = 11
total kids = 9
total number of trophies = 9 * 11 = 99 which contradicts the fact the total number of trophies are 100
2)
Suppose that person has less than 2 cups of coffee a day
Total cups of coffee = 400
he has bought at least one cup of coffee each day
which means
total number of cups of coffee = 1* 366 = 366 which contradicts the fact the person buys at least 400 cups of coffee in a year
3)
Average of three number = (a+ b+ c)/3
suppose that there are real numbers a, b, and c such that all three numbers are less than the average of the three numbers.
Let m be the average (a+b+c
)/3 = m. Then our assumption states that (a < m) and (b < m) and (c < m). By adding all the inequalities we get a + b + c < 3m. But m is defined to be (a+b+c)
/3 , so a + b + c = 3m. But now we have that 3m = a + b + c < 3m. So 3m < 3m which is an obvious contradiction. Thus our claim is true
Answer:
Try :
Semester_Fee = 8000.0
for x in range(1, 6):
import decimal
Semester_Fee = Semester_Fee + Semester_Fee *(3/(100*1.0))
if x==1:
print("In",x,"year, the tuition will be" ,'$', Semester_Fee, end='.')
else:
print("In",x,"years, the tuition will be" ,'$', Semester_Fee, end='.')
Answer:
I don't know if this is right output is {1,3}
Explanation:
