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2 years ago

Find the reciprocal of the expression. 10b/2b + 8

1 answer:

6 0

Comment
I think you need brackets to clarify what you mean. I think it should be written as
10b/(2b + 8)

If that is the case the reciprocal is

(2b + 8)/10b You just turn everything up side down. There are technical ways of doing this, but the easiest way is just to do what I just did.

Put the numerator in the denominator,
Put the denominator in the numerator.

You could simplify this a bit.
2b/10b + 8/10b
which reduces further.

1/5 + 4/5b
Just to make sure you understand where that b is, I will do this in

Latex. $\frac{2b + 8}{10b} = \frac{2b}{10b} + \frac{8}{10b} = \frac{2}{10} + \frac{4}{5b} = \frac{1}{5} + \frac{4}{5b}$

Alternate answer
If you do mean what your wrote then the reciprocal is 2b / 10b + 8 which is 1/5 + 8 = 8 + 0.2 = 8.2

The 8 has nothing to do with the reciprocal under these conditions.

The answer
I have given you all the choices I can think of without going into decimals. If you have choices, please list them under the comments.

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Sarah kept track of the points she scored during her first five basketball games in the table shown.

grandymaker [24]

Answer:

Step-by-step explanation:

If you add 22 onto the sum of all the points and divide by the amount of games (6), you get 12.

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2 years ago

Traffic speed: The mean speed for a sample of cars at a certain intersection was kilometers per hour with a standard deviation o

aliina [53]

Answer:

Step-by-step explanation:

Hello!

X₁: speed of a motorcycle at a certain intersection.

n₁= 135

X[bar]₁= 33.99 km/h

S₁= 4.02 km/h

X₂: speed of a car at a certain intersection.

n₂= 42 cars

X[bar]₂= 26.56 km/h

S₂= 2.45 km/h

Assuming

X₁~N(μ₁; σ₁²)

X₂~N(μ₂; σ₂²)

and σ₁² = σ₂²

<em>A 90% confidence interval for the difference between the mean speeds, in kilometers per hour, of motorcycles and cars at this intersection is ________.</em>

The parameter of interest is μ₁-μ₂

(X[bar]₁-X[bar]₂)± $t_{n_1+n_2-2}$ * $Sa\sqrt{\frac{1}{n_1} +\frac{1}{n_2} }$

$t_{n_1+n_2-2;1-\alpha /2}= t_{175; 0.95}= 1.654$

$Sa= \sqrt{\frac{(n_1-1)S_1^2+(n_2-1)S_2^2}{n_1+n_2-2} } = \sqrt{\frac{134*16.1604+41*6.0025}{135+42-2} } = 3.71$

[(33.99-26.56) ± 1.654 *( $3.71*\sqrt{\frac{1}{135} +\frac{1}{42} }$ )]

[6.345; 8.514]= [6.35; 8.51]km/h

<em>Construct the 98% confidence interval for the difference μ₁-μ₂ when X[bar]₁= 475.12, S₁= 43.48, X[bar]₂= 321.34, S₂= 21.60, n₁= 12, n₂= 15</em>

$t_{n_1+n_2-2;1-\alpha /2}= t_{25; 0.99}= 2.485$

$Sa= \sqrt{\frac{(n_1-1)S_1^2+(n_2-1)S_2^2}{n_1+n_2-2} } = \sqrt{\frac{11*(43.48)^2+14*(21.60)^2}{12+15-2} } = 33.06$

[(475.12-321.34) ± 2.485 *( $33.06*\sqrt{\frac{1}{12} +\frac{1}{15} }$ )]

[121.96; 185.60]

I hope this helps!

3 0

2 years ago

Arrange the circles (represented by their equations in general form) in ascending order of their radius lengths. Tiles x2 + y2 −

sashaice [31]

When doing this, we would have to first straight them all out, and as we see above, they are just all over the place, and then, we would have to set them up as a sequence.

$\left[\begin{array}{ccc}5x2 + 5y2 - 20x + 30y + 40 = 0\end{array}\right]$ would be our first step in this problem mainly because it contains the most terms in this aspect.

Then we would then $x2 + y2 - 2x + 2y -1 = 0$ , then, $2x2 + 2y2 - 28x - 32y - 8 = 0$ .

These would only be our first 3 part of the sequence in this aspect.

The others would then be the following:

$\boxed{x2 + y2 + 12x - 2y - 9 = 0 } \ then \ , \boxed{x2 + y2 - 4x + 4y - 10 = 0} \\ \\ then \ \boxed{x2 + y2 - 8x - 6y -20 = 0}$

Thus, as we would have one more afterward, our last part of the sequence would then be the following.

$\boxed{\boxed{4x2 + 4y2 + 16x + 24y - 40 = 0}}$

I hope this was found helpful!

3 0

2 years ago

Read 2 more answers

What is the x-intercept of the line with the equation -2x+1/2y=18

Mkey [24]

The x-intercept is a point on the x-axis.
y=0 at every point on the x-axis.

-2x + 1/2(0) = 18

-2x = 18

Divide each side by -2 : x = -9

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2 years ago

Ava wants to figure out the average speed she is driving. She starts checking her car’s clock at mile marker 0. It takes her 4 m

VLD [36.1K]

<h2>Answer:</h2>

The average speed of car is: