Which of the following career roadblocks is completely out of your control

1 answer:

4 0

Hi there!

Here are some career roadblocks that are completely out of your control:

#1 Problems managing stress

#2 Death of loved ones

#3 Losing your job

#4 Accidents putting you in difficult positions (car accidents, stuff like that, etc.)

#5 Your fellow co-workers treating you harshly (though you may try to get them to like you)

These are just a few examples. Hope this helps!

You might be interested in

The scatterplot shows how many pass attempts and yards a quarterback has in different football games. Notice that the line passe

Minchanka [31]

Answer:

Slope = 3

Explanation:

To find the slope, you divide the difference of the y-coordinates of 2 points on a line by the difference of the x-coordinates of those same 2 points .

4 0

2 years ago

A music store conducted a survey about whether people liked rock music, country music, or both. Out of the 800 respondents, 300

goblinko [34]

About like 260 people

8 0

1 year ago

Original works of authorship are protected by __________

Dafna1 [17]

Copyright, a form of intellectual property law, protects original works of authorship including literary, dramatic, musical, and artistic works, such as poetry, novels, movies, songs, computer software, and architecture. ... See Circular 1, Copyright Basics, section "What Works Are Protected."

Copyright

8 0

1 year ago

Read 2 more answers

Soon Yi loves to bake, and she is making flaky pastry. Soon Yi starts with a layer of dough 222 millimeters (\text{mm})(mm)left

frozen [14]

Answer:

3 times

Explanation:

When the dough is folded, it increases by a constant factor. We can model the growth of the thickness using the exponential growth model

$T(n)=T_0(1+r)^n$

Where:

Initial thickness, $T_0$ = 2mm

Growth factor, r =8%=0.08

We want to find the smallest number of times Soon Yi will have to roll and fold the dough so that the resulting dough is at least 2.5mm.

i.e When $T(n)\geq 2.5$ mm$

$2(1+0.08)^n\geq 2.5\\2(1.08)^n\geq 2.5\\$Divide both sides by 2$\\\dfrac{2(1.08)^n}{2}\geq \dfrac{2.5}{2}\\\\1.08^n\geq 1.25\\\\$Change to logarithm form\\n \geq \log_{1.08}1.25\\\\n\geq \dfrac{\log 1.25}{\log 1.08} \\\\n\geq 2.9$