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Lena [83]
2 years ago
8

You have a shelf that holds 25 1/2 pounds. How many 1 1/4 pound books can the shelf hold? Explain your response

Mathematics
1 answer:
-Dominant- [34]2 years ago
3 0

25.5 \div 1.25 =
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A catalog is discounting all sweaters 25%. How much will you pay for a sweater that is regularly $49.99? (A) $24.99 (B) $37.49 (
rodikova [14]
B becuase of 49.99 times .75
6 0
2 years ago
Mrs Stokes bought 3 packages of fruit juice. Each pkg has 2 rows of 6 boxes in each row. How many boxes of fruit juice did Mrs.
uysha [10]
Do 2x6=12×3 since there is 3 packages 2 rows and 6 in each row
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2 years ago
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An urn contains 2 red marbles and 3 blue marbles. 1. One person takes two marbles at random from the urn and does not replace th
Strike441 [17]
<h2>Answer with explanation:</h2>

Given : An urn contains 2 red marbles and 3 blue marbles.

Total marbles = 2+3=5

a) The general ways in which the person could get a red marble and a blue marble are :

1)  He draws red marble first and then second marble as blue.

2)  He draws blue marble first marble and then second marble as red.

b)  The number of ways to get one red and one blue marble is given by :-

^2C_1\times^3C_1=2\times3=6                          (i)

c) Number of ways to get 2 marbles from 5 is given by :-

^5C_2=\dfrac{5!}{2!(5-2)!}=\dfrac{5\times4\times3!}{3!\times2}=10     (ii)

Now, The probability the person gets a red and a blue marble will be :-

P(R\ \&B)=\dfrac{6}{10}=0.6       [Divide (i) by (ii)]

Hence, the  probability the person gets a red and a blue marble= 0.6

5 0
2 years ago
Consider the set of differences, denoted with d, between two dependent sets: 84, 85, 83, 63, 61, 100, 98. Find the sample standa
sveta [45]

Answer:

The sample standard deviation is 15.3.

Step-by-step explanation:

Given data items,

84, 85, 83, 63, 61, 100, 98,

Number of data items, N = 7,

Let x represents the data item,

Mean of the data points,

\bar{x}=\frac{84+85+83+63+61+100+98}{7}

=82

Hence, sample standard deviation would be,

\sigma= \sqrt{\frac{1}{N-1}\sum_{i=1}^{N} (x_i-\bar{x})^2}

=\sqrt{\frac{1}{6}\sum_{i=1}^{7} (x_i-82)^2}

=\sqrt{\frac{1}{6}\times 1396}

=\sqrt{232.666666667}

=15.2534149182

\approx 15.3

4 0
2 years ago
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