Absolute value cannot be less than 0
Solve Absolute Value.<span><span>|<span>x−5</span>|</span>=<span>−1</span></span>No solutions.
<span>|<span><span>−6</span>−<span>2x</span></span>|</span>=8
<span>x=<span>−<span><span>7<span> or </span></span>x</span></span></span>=<span>1
</span>
<span>|<span><span>5x</span>+10</span>|</span>=10
<span>x=<span><span>0<span> or </span></span>x</span></span>=<span>−4</span>
<span>|<span><span>−<span>6x</span></span>+3</span>|</span>=<span>0
</span>
So your answer is D) |–6x + 3| = 0
Answer:
0
Step-by-step explanation:
f(x) = √(x) + 12
g(x) = 2√(x)
(f-g)(x) = √(x) + 12 - 2√(x)
(f-g)(x) = 12 - √(x)
if x = 144
(f-g)(144) = 12 - √(144) = 12 - 12 = 0
Answer:
(5x²+2y² + 2xy)(5x²+2y²-2xy)
Step-by-step explanation:
25x⁴+4x²y²+4y⁴= (5x²)²+2*5x²*2y²+(2y²)² - 16x²y²= (5x²+2y²)² - (4xy)²= (5x²+2y² + 2xy)(5x²+2y² - 2xy)
Answer:
your... syllabus is different from mine....
Step-by-step explanation:
which class u study
First find how much she makes per day for the 16 pages. Then divide it by the amount of hours she works to find her hourly average. So I guess you can use all these proportions.