Answer:
c. 10°C
Explanation:
Given that: A slice of pizza has 500 kcal.
That is to say Q = 500kcal
If the pizza was burned and all the heat were used to warm a 50-L container of cold water,
what would be the approximate increase in the temperature of the water?
We were also being told to note that; A liter of cold water weighs about 1 kg.
i.e 50-L container weighs about 50kg (mass)
∴ Since;
Q= 500kcal,
m = 50kg; &
the specific heact (c) = 1
we can find the approximate increase in the temperature of the water by using the formula:
Q = mcΔT
ΔT = 
ΔT = 
ΔT = 10°C
Answer:
C. About 18 percent of the variation in blood pressure can be explained by a linear relationship between blood pressure and caffeine consumed.
Explanation:
Here, r = 0.428
∴ We can say it will give a positive curve, as 0.428 indicates it is a positive correlation.
Though the amount of correlation is low, still it is positive and more than 0.4
So, nearly about 18% of the variation in the blood pressure can be observed by the consumption of caffeine water. As consumption of caffeine water and blood pressure is both increasing so we can say that r= 0.428 will give a positive linear curve.
Answer:1. They allow the movement of molecules from one cell to another, enabling communication between cells.
Explanation:the cell wall is a rigid and cellulose containing wall, which surrounds the plasma membrane.
During lignification, small pores appear on the cell wall through which cytoplasmic strands extend.these pores are the plasmodesmata,which provides connections between plant cells
Answer:
Explanation:
This question is incomplete. However, what is described in this question is a method of DNA damage repair mechanism. The method described is called base excision repair. Generally, glycosylases play important roles in base excision repair (as they detect and remove these damaged bases).
One thing that can be considered while identifying the bond to be broken is the codon that will be formed after the removal of base. If this codon (a three base sequence) will still produce the same protein as when a normal cytosine was present.
NOTE: During this base excision repair, a glycosylase will detect and remove the damaged cytosine. Once removed, the remaining nucleotide backbone (of the removed cytosine) is also removed and the gap is filled and sealed by other enzymes in this repair mechanism.
