Question

It takes Tyler twice as long as Kyle to complete the same job. When the men work together, they can complete the job in 6 hours. How many hours are required for Tyler to do the job alone? Enter your answer in the box.

Answer 1

Answer: Time taken by Tyler to do the job alone =18 days.

Explanation:

Since we have given that

Tyler takes twice as long as Kyle to complete the same job,

Let the work done by Kyle in 1 day be

$\frac{1}{x}$

Let the work done by Tyler in 1 day

$\frac{1}{2x}$

If the men work together , they can complete the work in 6 hours.

According to question, we get

$\frac{1}{x}+\frac{1}{2x}=\frac{1}{6}\\\\\implies \frac{2+1}{2x}=\frac{1}{6}\\\\\implies \frac{3}{2x}=\frac{1}{6}\\\\\implies x=9$

Hence, time taken by Kyle is x= 9 hours

and

Time taken by Tyler to do the job alone is given by

$2x=2\times 9=18\ hours$

Answer 2

Answer

Tyler to do the job alone =18/1 = 18 hrs

Solution

It takes Tyler twice as long as Kyle to complete the same job.

efficiency of Kyle  is twice the efficiency of Tyler  

Let x be the efficiency of Tyler the efficiency of Kyle is 2x

efficiency of Tyler  : efficiency of Tyler = x :2x =1:2

Therefore total efficiency = 1 + 2 =3x

The total job = efficiency x total time

Here total time to complete the job=6 hrs

Total job =18

Time taken to complete the job =Total job/efficiency

Tyler to do the job alone =18/1 = 18 hrs

Kyle to do the job alone =18/2 = 9 hrs