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Aleks04 [339]
2 years ago
8

a car rental service rently purchased all new vehicles .to help cover the cost ,rental rates have to increase 26% from the norma

l rate $45.00 per day. what should the new rate be
Mathematics
1 answer:
ruslelena [56]2 years ago
5 0

Answer:

The new rate should be $56.67 per day

Step-by-step explanation:

Proportion states that the two fractions or ratios are equal.

As per the statement:

Normal rate per day = $45

To find the new rate:

Let new rate be x per day

By definition of proportion:

\frac{126}{100} = \frac{x}{45}

By cross multiply we have;

100x = 126 \times 45

Divide both sides by 100 we get;

x = \frac{126 \times 45}{100}

Simplify:

x = $56.7

Therefore, the new rate should be $56.7 per day




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The admission fee at a movie theater is $5 for children and $9 for adults. If 3200 people go to the movies and $24000 is collect
Usimov [2.4K]
For this problem, let x be the number of children and y for adults. Formulate the equations: 1st equation, x + y = 3,200 and 2nd equation 5x + 9y = 24,000. Re-arrange 1st equation into x = 3200 - y. Then, substitute into 2nd equation, 5(3,200-y) + 9y = 24,000. Then, solve for y. The 16,000 - 5y + 9y = 24000. Final answer is, y = 2000 adults went to watch the movie.
6 0
2 years ago
Match each type of function with a characteristic of its graph. Enter the letter of the correct characteristic next to the type
Lerok [7]

Answer:

Linear Function: Its graph has a constant slope (D).

Quadratic Function: Its graph is a parabola (B).

Inverse Variation Function: Its graph has both a horizontal asymptote and a vertical asymptote (F).

Square-root Function: Its graph has a closed endpoint (A).

Exponential Function:  Its graph has a horizontal asymptote, but not a vertical asymptote (C).

Logarithmic Function: Its graph is a reflection of the graph of an exponential function in the line <em>y = x  </em>(E).

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2 years ago
Read 2 more answers
Two production lines produce the same parts per week of which 100 are defective. Line 2 produces 2,000 parts per week of which 1
Vikentia [17]

Answer:

(a) 0.0833 or 8.33%

(b) 0.40 or 40%

Step-by-step explanation:

Parts line one (n1) = 1,000 parts

Defects line one (d1) = 100 parts

Parts line two (n2) = 2,000 parts

Defects line two (d2) = 150 parts

Total number of parts (n) = 3,000 parts

a. Probability of a randomly selected part being defective:

P(d) = \frac{d_1+d_2}{n_1+n_2}=\frac{100+150}{1,000+2,000}\\P(d) =0.0833=8.33\%

The probability is 0.0833 or 8.33%

b. Probability of a part being produced by line one, given that it is defective:

P(1|d)=\frac{P(1\cap d)}{P(1\cap d)+P(2\cap d)}\\P(1|d)=\frac{\frac{100}{3,000} }{\frac{100}{3,000}+\frac{150}{3,000}}\\P(1|d)=0.4 = 40\%

The probability is 0.40 or 40%.

5 0
2 years ago
In the figure below, \overline{AD} AD start overline, A, D, end overline and \overline{BE} BE start overline, B, E, end overline
VLD [36.1K]

Answer:

<u>The measure of the arc CD = 64°</u>

Step-by-step explanation:

It is required to find the measure of the arc CD in degrees.

So, as shown at the graph

BE and AD are are diameters of circle P

And ∠APE is a right angle ⇒ ∠APE = 90°

So, BE⊥AD

And so, ∠BPE = 90° ⇒(1)

But it is given: ∠BPE = (33k-9)° ⇒(2)

From (1) and (2)

∴ 33k - 9 = 90

∴ 33k = 90 + 9 = 99

∴ k = 99/33 = 3

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By substitution with k

<u>∴ The measure of the arc CD = 20*3 + 4 = 60 + 4 = 64°</u>

6 0
2 years ago
Given directed line segment QS , find the coordinates of R
Degger [83]

Answer:

The answer is below

Step-by-step explanation:

The question is not complete, what are the coordinates of point Q and R. But I would show how to solve this.

The location of a point O(x, y) which divides line segment AB in the ratio a:b with point A at (x_1,y_1) and B(x_2,y_2) is given by the formula:

x=\frac{a}{a+b}(x_2-x_1)+x_1\\ \\y=\frac{a}{a+b}(y_2-y_1)+y_1

If point Q is at (x_1,y_1) and S at (x_2,y_2)  and R(x, y) divides QS in the ratio QR to RS is 3:5, The coordinates of R is:

x=\frac{3}{3+5}(x_2-x_1)+x_1=\frac{3}{8}(x_2-x_1)+x_1\\ \\y=\frac{3}{3+5}(y_2-y_1)+y_1=\frac{3}{8}(y_2-y_1)+y_1

Let us assume Q(−9,4) and S(7,−4)

x=\frac{3}{8}(7-(-9))+(-9)=\frac{3}{8}(16)-9=-3\\\\y=\frac{3}{8}(-4-4)+4=\frac{3}{8}(-8)+4=1

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2 years ago
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