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WARRIOR [948]
2 years ago
4

Graph the functions and approximate an x-value in which the exponential function surpasses the polynomial function. In your fina

l answer, include a copy of the graph. y = 2x2 + 7 y = 5(x-4)

Mathematics
1 answer:
bearhunter [10]2 years ago
6 0

Answer:

x-value is 6.87

Step-by-step explanation:

we are given

Polynomial as

y=2x^2+7

Exponential as

y=5^{x-4}

Firstly, we can draw graph

We can see that intersection point is (6.87,101.392)

so, x=6.87


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Choose the product. -7p 3(4p 2 + 3p - 1)
DIA [1.3K]

Answer:

14p -3

Step-by-step explanation:

-7p 3(4p 2+3p - 1)

3x4= 12p

3x3=9p

12+9= 21

21-7=14p

3x2=6

3x-3=-9

-9 +6= -3

= 14p -3

hope this helps :)

7 0
1 year ago
A club is making posters to raise money. The printing company charges a base fee of $60 and $2 per poster. How many posters can
Ad libitum [116K]

Answer:

120 posters

Step-by-step explanation:

300 - 60 = 240

240/2 = 120

8 0
2 years ago
Read 2 more answers
Distributed property for 0.75(3.5a-6b)
Alika [10]
0.75(3.5a -6b)
= 0.75* (3.5a) -0.75* (6b) (distributive property)
= 2.625a -4.5b

The final answer is 2.625a -4.5b~
5 0
2 years ago
In choice situations of this type, subjects often exhibit the "center stage effect," which is a tendency to choose the item in t
victus00 [196]

Complete Question

The complete question is shown on the first uploaded image

Answer:

a

The probability that he or she would choose the pair of socks in the center position is   p =\frac{1}{5}

The correct answer choice is

X has a binomial distribution with parameters n=100 and p=1/5  

b

The mean is  \mu = 20

The standard deviation is \sigma=4

c

The probability, P =0.0002

d

The correct answer is

The experiment supports the center stage effect. If participants were truly picking the socks at random, it would be highly unlikely for 34 or more to choose the center pair.

Using the R the probability Pe = 0.0003

The probabilities P \approx Pe

Step-by-step explanation:

Since the person selects his or her desired pair of socks at random , then the probability that the person would choose the pair of socks in the center position from all the five identical pair is mathematically evaluated as

                  p =\frac{1}{5}

                    =0.2

The mean of this distribution is mathematical represented as

           \mu = np

substituting the value

         \mu = 100 * 0.2

             \mu = 20

The standard deviation is mathematically represented as

         \sigma = \sqrt{np (1-p)}

substituting the value

           = \sqrt{100 * 0,2 (1-0.2)}

           \sigma=4

Applying normal approximation the probability that 34 or more subjects would choose the item in the center if each subject were selecting his or her preferred pair of socks at random would be mathematically represented as

               P=P(X \ge 34 )

By standardizing the normal approximation we have that

              P(X \ge 34) \approx P(Z \ge z)

Now z is mathematically evaluated as

               z = \frac{x-\mu}{\sigma }

Substituting values

             z = \frac{34-20}{4}

               =3.5

So  using the z table the P(Z \ge 3.5) is  0.0002

The probability P and Pe that 34 or more subject would choose the center pair is very small  So

The correct answer is

The experiment supports the center stage effect. If participants were truly picking the socks at random, it would be highly unlikely for 34 or more to choose the center pair.

 

6 0
2 years ago
In a car lot, the ratio of the number of new cars to the number of pre owned cars is 6 to 5. The total number of new and preowne
RUDIKE [14]

Answer:

im soory got to gt to class ill make sure i thank u and answer a nother of ur questions sorry ccoykdnt answer.

Step-by-step explanation:

8 0
2 years ago
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