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crimeas [40]
2 years ago
7

Drag each expression to show whether it is equivalent to 6(4x−1), 24x+6, or (4⋅6x)+(4⋅2) somebody please help me i need to get t

his right

Mathematics
1 answer:
faltersainse [42]2 years ago
5 0

Answer:

6(4x-1) is equivalent to 24x-6 and (2*12x)-(2*3)

24x+6 is equivalent to 6(4x+1) and (6*4x)+(6*1)

(4*6x)+(4*2) is equivalent to 24x+8 and 4(6x+2)

Step-by-step explanation:

An equivalent expression is an expression which either simplified or factored is equal to it.

6(4x-1) is equivalent to 24x-6 and (2*12x)-(2*3)

24x+6 is equivalent to 6(4x+1) and (6*4x)+(6*1)

(4*6x)+(4*2) is equivalent to 24x+8 and 4(6x+2)

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Which linear equation represents on the graph
s2008m [1.1K]

Remember, rise/run is the easiest way to determine slope

y=mx+b is form

mx is slope, whilst b is y int

so, answer? y=-3x-2

Or A.

4 0
2 years ago
Is the right arm or left arm stronger? Twenty five right handed people were studied. They were asked to do as many bicep curls a
melisa1 [442]

Answer:

The p-value should be higher than 0.05

Step-by-step explanation:

solution is found below

5 0
1 year ago
Find a matrix P such that PTAP orthogonally diagonalizes A. Verify that PTAP gives the proper diagonal form. (Enter each matrix
krok68 [10]

Answer:

the P matrix you are looking for is P=(1/\sqrt{2}) · [[1 1 0 0],[1 -1 0 0],[0 0 1 1],[0 0 1 -1]]

Step-by-step explanation:

Answer:

For an orthogonal diagonalization of any matrix you have to:

1º) Find the matrix eigenvalues in a set order.

2º) Find the eigenvectors of each respective eigenvalues.

Tip: You can write the matrix A like A = P^{t} D P

3º) D is the diagonal matrix with each eigenvalue (in order) in the diagonal.

4º) Write P as the normalized eigenvectors in order (in columns).

Tip 2: Remember, P^{t}·P = I, so if A = P^{t} D P, then:

P A P^{t} = P  P^{t} D P P^{t} = I D I = D

So the P we are looking for is the P^{t} of the diagonalization.

Tip 3: In this case, A is a block matrix with null nondiagonal submatrixes, therefore its eigenvalues can be calculated by using the diagonal submatrixes. The problem is reduced to calculate the eigenvalues of A₁₁ = A ₂₂ = [[5 3],[3 5]]

Solving:

1º)the eigenvalues of A₁₁ are {8,2}, therefore the D matrix is \left[\begin{array}{cccc}8&0&0&0\\0&2&0&0\\0&0&8&0\\0&0&0&2\end{array}\right]

2º) the eigenvectors of A₁₁ are P₈= {[1 1]T} P₂= {[1 -1]T}, therefore normalizing the eigenvectors you obtain P = (1/\sqrt{2}) · [[1 1 0 0],[1 -1 0 0],[0 0 1 1],[0 0 1 -1]] (you can see that P =  P^{t} in this case).

As said in "tip 2": P A P^{t} = P  P^{t} D P P^{t} = I D I = D

So the P obtained is the one you are looking for.

4 0
2 years ago
The table shows data gathered by an environmental agency about the decreasing depth of a lake during the first few months of a d
EastWind [94]
(0,346)(2,344.8)
slope = (344.8 - 346) / (2 - 0) = -1.2 / 2 = -0.6

y = mx + b
slope(m) = -0.6
use either of ur points (0,346)...x = 0 and y = 346
now we sub and find b, the y int
346 = -0.6(0) + b
346 = b

so ur equation is : y = -0.6x + 346

after 4 weeks....x = 4
y = -0.6(4) + 346
y = -2.4 + 346
y = 343.6 <=== after 4 weeks it will be 343.6 
5 0
1 year ago
N 2004, the General Social Survey (which uses a method similar to simple random sampling) asked, "Do you consider yourself athle
zmey [24]

<u>Answer-</u>

The standard error of the confidence interval is 0.63%

<u>Solution-</u>

Given,

n = 2373 (sample size)

x = 255 (number of people who bought)

The mean of the sample M will be,

M=\frac{x}{n} =\frac{255}{2373} =0.1075

Then the standard error SE will be,

SE=\sqrt{\frac{M\times (1-M)}{n}}

SE=\sqrt{\frac{0.1075\times (1-0.1075)}{2373}}=\sqrt{\frac{0.0959}{2373}}=0.0063=0.63\%

Therefore, the standard error of the confidence interval is 0.63%




6 0
2 years ago
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