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gizmo_the_mogwai [7]
2 years ago
3

A 100 gram sample of Cerium-143 has a half life of 33 hours. How Long will it take until there are only 6.25 grams of cerium-143

left?
Biology
2 answers:
AysviL [449]2 years ago
5 0
Q. 
a 100 - gram sample of cerium-143 has a half life of 33 hours. how long will it take until there are only 6.25 grams of cerium-143 left?


answer 132 hours
Dvinal [7]2 years ago
5 0

<u>Answer:</u> The time taken by Cerium-143 will be 132.051 hours.

<u>Explanation:</u>

All the decay processes follow first order kinetics.

The equation used to calculate half life for first order kinetics:

t_{1/2}=\frac{0.693}{k}

where,

t_{1/2} = half life of the reaction = 33 hours

k = ?

Putting values in above equation, we get:

k=\frac{0.693}{33hrs}=0.021hrs^{-1}  

Rate law expression for first order kinetics is given by the equation:

t=\frac{2.303}{k}\log\frac{a}{a-x}

where,  

k = rate constant = 0.021hrs^{-1}

t = time taken for decay process = ? hours

a = initial amount of the reactant  = 100 grams

a - x = amount left after decay process  = 6.25 grams

Putting values in above equation, we get:

t=\frac{2.303}{0.021hrs^{-1}}\log\frac{100g}{6.25g}\\\\t=132.051hours

Hence, the time taken by Cerium-143 will be 132.051 hours.

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Hello. This question is incomplete. Also, you forgot to show the flowchart. The flowchart is attached below and the full question is:

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