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Natali [406]
2 years ago
10

Select the correct answer. What is the surface area of the victory podium shown here? Include all surfaces of the podium, includ

ing the bottom.
A. 61.5 square feet

B. 61.75 square feet

C. 65.25 square feet

D. 69 square feet

Mathematics
1 answer:
Leya [2.2K]2 years ago
4 0

Answer:

Option C is correct.

Step-by-step explanation:

Given the dimension of the surfaces i.e length, width and height of podium. we have to calculate the surface area of the victory podium.

As Surface area of cuboid is 2(LW+WH+HL)

In the given figure, the upper cuboid has dimension

L=2.5 ft. , W=1.5 ft, H=1.5 ft

\text{Surface area=}2(2.5(1.5)+1.5(1.5)+1.5(2.5))=19.5ft^2

\text{Area of bottom face of upper cuboid=}L\timesW=2.5\times1.5=3.75ft^2

The upper face is occuring twice therefore it must be subtracted to find the area

Dimensions of lower podium are

L=7.5 ft. , W=1.5 ft, H=1.5 ft

\text{Surface area=}2(7.5(1.5)+1.5(1.5)+1.5(7.5))=49.5ft^2

Now, Surface area of podium included bottom is

19.5+49.5-3.75=65.25 square feet.

Hence, option C is correct.

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Answer:

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Step-by-step explanation:

we know that

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so

sin(30\°)=cos(60\°)

sin(60\°)=cos(30\°)

Because

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In this problem the product of

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is equal to

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therefore

sin(30\°)*sin(60\°)=cos(60\°)*cos(30\°)

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A 12 oz bottle of clean green dish soap is $1.09 while a 20 oz bottle cost 1.99 which is the better to buy
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The 12 oz

Step-by-step explanation:

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Answer:

Is plausible that the successive throws are independent

Step-by-step explanation:

1) Table with info given

The observed values are given by the following table

__________________________________________________

First shot          Made          Second shot missed           Total

__________________________________________________

Made                  152                       33                                185

Missed                37                         8                                  45

__________________________________________________

Total                    189                       41                                230

2) Calculations and test

We are interested on check independence and for this we need to conduct a chi square test, the next step would be find the expected value:

Null hypothesis: Independence between two successive free throws

Alternative hypothesis: No Independence between two successive free throws

_____________________________________________________

First shot                    Made                                    Second shot missed

_____________________________________________________

Made                  189(185)/230=152.0217                41(185)/230=32.9783

Missed                189(45)/230=36.9783                  41(45)/230=8.0217

_____________________________________________________

On this case all the expected values are higher than 5 and the sample size 230 is enough to apply the chi squared test.

3) Calculate the chi square statistic

The statistic for this case is given by:

\chi_{cal}^2 =\sum \frac{(O_i -E_i)}{E_i}

Where O represent the observed values and E the expected values. Replacing the values that we got we have this

\chi_{cal}^2 =\frac{(152-152.0217)^2}{152.0217}+\frac{(33-32.9783)^2}{32.9783}+\frac{(37-36.9783)^2}{36.9783}+\frac{(8-8.0217)^2}{8.0217}=0.000003098+0.00001428+0.00001273+0.0.00005870=0.00008881

Now with the calculated value we can find the degrees of freedom

df=(r-1)(c-1)=(2-1)(2-1)=1 on this case r means the number of rows and c the number of columns.

Now we can calculate the p value

p_v =P(\chi^2 >0.00008881)=0.9925

On this case the pvalue is a very large value and that indicates that we can fail to reject the null hypothesis of independence. So is plausible that the successive throws are independent.

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