<span>The F2 generation would have included a higher percentage of pea plants producing round, yellow peas. As the f2 generation included 315 plants producing round yellow peas, 108 with round green peas, 101 with wrinkled yellow peas, and 32 with wrinkled green peas which all are in the ratio 9:3:3:1.</span>
Answer: clustered population distribution
Explanation:
Answer:
a. Anabolic pathways build molecules, require energy, and are endergonic.
Explanation:
<em>Anabolic pathway </em>describes the metabolic reactions that<em> </em><em>build up</em><em> complex molecules from simpler ones</em>, typically via condensation (monomers covalently joined producing water as a by-product).<em> It </em><em>requires energy </em><em>to construct new bonds, this means is </em><em>endergonic</em><em>.</em>
The catabolic pathway, on the other hand, describes metabolic reactions that<em> </em><em>break complex molecules down </em><em>into simple ones</em>, typically via hydrolysis (consumption of water to break bonds within the polymer). <em>It </em><em>releases energy </em><em>when these bonds are broken, this means it is </em><em>exergonic</em><em>.</em>
Considering this information we can conclude that the correct answer is a. Anabolic pathways build molecules, require energy, and are endergonic.
I hope you find this information useful and interesting! Good luck!
Use the Hardy Weinburg
equation of allelic frequency.
P2+2pq+q2=1
174/1378 = 0.126 = q2
Therefore q2 = 0.126; q = 0.355
If q = 0.355 and we understand that p + q = 1, then
P = 1 – 0.355 = 0.645
To find homozygous dominant population (p2);
(0.645)2 x 1378 = 0.416 x 1378 = 573
Heterozygous popualiton (2pq);
(2 x 0.645 x 0.355) x 1378 = 0.458 x 1378= 631
Recessive indviduals (q2) = 174
I believe the answer would be sedimentary rocks.
