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kolezko [41]
2 years ago
5

Using the seismic reading received at Station 1 only, an observer would be able to determine

Geography
1 answer:
hoa [83]2 years ago
3 0

Answer

<u>Neither the distance nor the direction of the epicenter from station 1</u>

Explanation

A single seismic reading received at station 1 only will tell the observer that the ground shook at that location and the intensity. Without other data  and information, the observer cannot make any other meaningful conclusions. A minimum of three seismograph stations are required before an observer can determine/ conclude meaningful results.

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Which of the following events would be considered a migration push factor ?
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5. How fast did the shoes travel? (4 points) a. From where the shoes spilled (48°N, 161°W) to where they first made landfall (49
Leto [7]

Answer:

a) d = 35.0143 Km

t = 188 days

v = 7.76*10⁻³ Km/h

b) d = 28.6356 Km

t = 2165 days

v = 5.51*10-4 Km/h

Explanation:

a. From where the shoes spilled (48°N, 161°W) to where they first made landfall (49°N, 126°W), how many kilometers did they travel?  

We can use the equation

d = √(∆N²+∆W²)

⇒   d = √((49-48)²+(126-161)²) = 35.0143 Km

How many days did they take to travel that distance? (You can use November 30 as the date found).  

From May 27, 1990 to November 30, 1990 we have

t = 5 days + (30 days/month)*(3 months) + (31 days/month)*(3 months) = 188 days

⇒   t = 188 days = (188 days)*(24 hours/day) = 4512 hours

What was their rate of travel in kilometers per hour?  

We use the equation

v = d/t   ⇒   v =  35.0143 Km/ 4512 h

⇒   v = 7.76*10⁻³ Km/h

b. From where the shoes spilled (48°N, 161°W) to where they were found in 1996 (54°N, 133°W), how many kilometers did they travel?  

We can use the equation

d = √(∆N²+∆W²)

⇒   d = √((54-48)²+(133-161)²) = 28.6356 Km

How many days did they take to travel that distance (use April 30 as the date found)?  

From May 27, 1990 to April 30, 1996 we have

t = 5 days + (30 days/month)*(4 months) + (31 days/month)*(6 months) + 29 days + (365 days/ year)*(4 years)+ (366 days/ year)*(1 year)= 2165 days

⇒   t = 2165 days = (2165 days)*(24 hours/day) = 51960 hours

What was their rate of travel in kilometers per hour?

We use the equation

v = d/t   ⇒   v =  28.6356 Km/ 51960 h

⇒   v = 5.51*10-4 Km/h

7 0
2 years ago
Adam, who is 5'6" tall, notices his shadow on the sidewalk. If the angle of elevation from the tip of the shadow to the sun is 6
german
<h2>Answer:</h2>

This problem can be solved using trigonomtry, assuming that the figure formed by Adam's shadow and Adam himself is a Right Triangle (as shown in the figure attached).


According to this,  the distance from the tip of the shadow to the top of Adam's head is the hypotenuse H of the triangle, and we already know Adam's height and the angle of elevation. So, the trigonometric function that best works in this case is sine:


sen(angle)=\frac{Oppositeleg}{hypotenuse}  


Where the opposite leg is the side of the triangle that is opposite to the 60\º angle.

In this especific case:


sen(60\º)=\frac{5.6feet}{H}     (1)


In order to know the value of the hypotenuse we have to find  H from equation (1):

H=\frac{5.6feet}{sen(60\º)}



H=6.4663 feet



Rounding:

H=6.46 feet>>>>>This is the distance from the tip of the shadow to the top of Adam's head



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