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2 years ago

Use the converse of the side-splitter theorem to determine if . Which statement is true?

Mathematics

2 answers:

Whitepunk [10]2 years ago

6 0

Answer:

The answer to this question is the first option:

Line segment TU is parallel to line segment RS because 32/36=40/45

Zepler [3.9K]2 years ago

6 0

Answer:

The correct option is 1.

Step-by-step explanation:

From the given figure it is clear that QT=32, TR=36, QU=40 and US=45.

The converse of side splitter theorem states that if a line divides two sides proportionally, then that line is parallel to the third side.

The ratio in which TU divides the two sides is

$\frac{QT}{TR}=\frac{32}{36}=\frac{8}{9}$

$\frac{QU}{US}=\frac{40}{45}=\frac{8}{9}$

$\frac{QT}{TR}=\frac{QU}{US}=\frac{8}{9}$

It means the line TU divides two sides proportionally.

Using converse of side splitter theorem, Line segment TU is parallel to line segment RS because

$\frac{32}{36}=\frac{40}{45}$

Therefore the correct option is 1.

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Two processes are used to produce forgings used in an aircraft wing assembly. Of 200 forgings selected from process 1, 10 do not

tangare [24]

Answer:

$\bar p_1=0.05\\\bar p_2=0.067$

b-Check illustration below

c.(-0.0517,0.0177

Step-by-step explanation:

a.let $p_1 \& p_2$ denote processes 1 & 2.

For $p_1$ : T1=10,n1=200

For $p_2$ :T2=20,n2=300

Therefore

$\bar p_1=\frac{t_1}{N_1}=\frac{10}{200}=0.05\\\bar p_2=\frac{t_2}{N_2}=\frac{20}{300}=0.067$

b. To test for hypothesis:-

$H_0:p_1=p_2\\H_A=p_1\neq p_2\\\alpha=0.05$

ii.For a two sample Proportion test

$Z=\frac{\bar p_1-\bar p_2}{\sqrt(\bar p(1-\bar p)(\frac{1}{n_1}+\frac{1}{n_2})}\\$

iii. for $\frac{\alpha}{2}=(-1.96,+1.96)$ (0.5 alpha IS 0.025),

reject $H_o$ if $|Z|>1.96$

iv. Do not reject $H_o$ . The noncomforting proportions are not significantly different as calculated below:

$z=\frac{0.050-0.067}{\sqrt {(0.06\times0.94)\times \frac{1}{500}}}$

z=-0.78

c. $(1-\alpha).100\%$ for the p1-p2 is given as:

$(\bar p_1-\bar p_2)\pm Z_0_._5_\alpha \times \sqrt \frac{ \bar p_1(1-\bar p_1)}{n_1}+\frac{\bar p_2(1-\bar p_2)}{n_2}\\\\=(0.05-0.067)\pm 1.645 \times \sqrt \ \frac{0.05+0.95}{200}+\frac{0.067+0.933}{300}\\$

=(-0.0517,+0.0177)

*CI contains o, which implies that proportions are NOT significantly different.

4 0

2 years ago

P=100a÷t solve for a

pishuonlain [190]

a=1/100pt is the correct answer. First you had to multiply by t from both sides of equation, and it gave us, ⇒ $pt=100a$ . And then you had to flip an equation, and it gave us, ⇒ $100a=pt$ . You can also divide by one-hundred (100) from both sides of equation, and it gave us, $\frac{100a}{100}=\frac{pt}{100}$ . And finally, and it gave us the answer is a=1/100pt is the final answer. Hope this helps! And thank you for posting your question at here on brainly, and have a great day. -Charlie