Values which are proportional are represented by the Greek letter ‘Alpha’
So if A is proportional to B
We put the Alpha symbol between A and B to represent it
Answer:
<h2>It must be shown that both j(k(x)) and k(j(x)) equal x</h2>
Step-by-step explanation:
Given the function j(x) = 11.6
and k(x) = 
, to show that both equality functions are true, all we need to show is that both j(k(x)) and k(j(x)) equal x,
For j(k(x));
j(k(x)) = j[(ln x/11.6)]
j[(ln (x/11.6)] = 11.6e^{ln (x/11.6)}
j[(ln x/11.6)] = 11.6(x/11.6) (exponential function will cancel out the natural logarithm)
j[(ln x/11.6)] = 11.6 * x/11.6
j[(ln x/11.6)] = x
Hence j[k(x)] = x
Similarly for k[j(x)];
k[j(x)] = k[11.6e^x]
k[11.6e^x] = ln (11.6e^x/11.6)
k[11.6e^x] = ln(e^x)
exponential function will cancel out the natural logarithm leaving x
k[11.6e^x] = x
Hence k[j(x)] = x
From the calculations above, it can be seen that j[k(x)] = k[j(x)] = x, this shows that the functions j(x) = 11.6 and k(x) = are inverse functions.
It is hard to say how Faelyn's work shows the polynomial is prime, but it is.
There are no factors of 6*4 = 24 that add to -5, so the polynomial cannot be factored using real numbers.
_____
The expression of suggestion 2 is a different polynomial than the one Faelyn is factoring.
Taking a factor of 2x out of the first group does not help it match the factoring of the second group.
Dividing one or the other of the groups by -1 will not make the binomials the same.
Im sure this website will help answer.com
<span> the probability that she rolls an odd number AND and pulls a red chip
so it is = Prob(odd no) * Prob(red chip)
Prob(odd no) for a fair die = 1/2
Prob(red chip) = red chip / total chip = 2/(2+1) = 2/3
so the ans is 1/2 * 2/3 = 1/3
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