Answer:
A. whether the glycoproteins or capsid proteins on its surface recognize those of the host cells.
Explanation:
Virus has different surface proteins that are recognized by the receptors present on its host cell. The range of a virus is determined by the recognition of these proteins by the host cell.
The interaction between the receptor on the host cell and surface proteins on the viral capsid is important for viral genome entry in the host cell and to determine the range of the host cells.
If the surface protein of the virus is not able to bind to the receptor on any cell then the virus can not infect the cell. For example, the HIV virus infects only those cell which have CD4 receptors. So the right answer is A.
Answer:
The correct answer is ''undergo irreversible repression.''
Explanation:
The morphological and physiological transformation of meristematic cells into adult or differentiated tissues constitutes the process of cell differentiation. This, and the consequent specialization of the cell, bring about the division of labor, forming cells with specific functions. Differentiation occurs by differential activation of some genes and repression of others. Depending on the position it occupies, each cell receives certain stimuli to develop the corresponding activities. During the differentiation process, cells undergo a series of changes in their characteristics and there is a readjustment in their mutual relationships.Different molecular factors initiate and drive the programming / reprogramming of cell fate through the modulation of specific genomic and epigenomic patterns, which regulate the expression of activator / repressor genes of the main fundamental and specialized cellular processes. Thus, the differentiated cell will express certain genes and acquire certain functions.Adult stem cells are responsible for maintaining the different types of specialized cells that make up the body. Asymmetric cell division in stem cells has emerged as one of the main physiological mechanisms that regulate the number of cells and their diversity to maintain tissue homeostasis. A large number of molecules, generically called determinants of cell fate, participate in the regulation of asymmetric division. Asymmetric division of somatic stem cells produces both a stem cell and a progenitor. The initial progenitor cells, through new cycles of asymmetric cell division, finally reach their terminal state of cell differentiation, due to changes in intracellular and extracellular (environmental) signaling. After cells leave their mother state and begin to differentiate, they make exclusive selections for phenotypic pathways through secondary genomic / epigenomic modifications, mainly to different types and gradients of transcription factors (physiological programming of cell differentiation). This leads, for example, to activation of specialized biosynthetic pathways, remodeling of the cytoskeleton, and repression of cell proliferation signaling. The expression of genes is regulated mainly at the level of their transcription. Transcription factors correspond to proteins with the ability to interact with specific DNA sequences and trigger their transcriptional activity. Most transcriptional factors contain different domains that participate in different aspects of protein function; they generally contain two domains: a domain that binds to specific DNA sequences and an activation domain that regulates transcription by interacting with other proteins. In the regulation of gene transcription, in addition to transcription factors, coactivating and corepressor molecules participate, which bind to them, modifying their activity in a positive or negative sense. Each cell type has a characteristic pattern of gene transcription, which is determined by the binding of combinations of transcription factors to the regulatory regions of a gene.
2 monosaccharides (glucose monomers) combined
Answer:
See the answer below
Explanation:
Let the disorder be represented by the allele a.
Since the disease is an autosomal recessive one, affected individuals will have the genotype aa and normal individuals will have the genotype Aa or AA.
Since the four adults are carriers, their genotypes would be Aa.
Aa x Aa
Progeny: AA 2Aa aa
Probability of being affected = 1/4
Probability of being a carrier = 1/2
Probability of not being affected = 3/4
(a) The chance that the child second child of Mary and Frank will have alkaptonuria = 1/2
(b) The chance that the third child of Sara and James will be free of the condition = 3/4
(c)
(d) If someone has no family history of the disorder, their genotype would be AA.
AA x aa
4 Aa
<em>The chance that a child with alkaptonuria will have an offspring with alkaptonuria if the child's mate has no family history </em>= 0
(e)
(f) <em>The chance that a child with alkaptonuria will have an offspring with alkaptonuria if the child's mate has no family history</em> = 0
Using
the image that represents the land-dwelling organism and an aquatic
single celled organism. The statement that best explains how A and B
are able to survive in their environments is…
Answer:
A) The organelles in B perform similar functions to the organ systems
in A.
Please
see image attached to better understand how we arrived to the
conclusion.
<span>I
hope it helps, Regards. </span>
