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amm1812
1 year ago
6

Use the model to explain how celiac disease interrupts the normal transportation of energy and other nutrients from the digestiv

e system to the circulatory system.

Biology
2 answers:
IrinaK [193]1 year ago
8 0

Answer:

According to the model, the "villi" of small intestines is being damaged as an impact of celiac disease. Small intestines are responsible for absorption of nutrients and minerals from food, this occurs through villi, in case of damaged villi absorption is interfered, thus disturbing the digestive system. If the nutrients, minerals or vitamins are not being absorbed well by small intestines then they will be excreted out of the body and will not be transported to the blood and other areas, this would result in deficiency of minerals and vitamins  in blood that cause weakness.

dexar [7]1 year ago
7 0

Answer: Plato Answer

The fingerlike shape of the villi is very important for nutrient absorption because it increases the surface area of the small intestine. In celiac disease, the villi flatten, decreasing the surface area of the small intestine. As a result, fewer nutrients get absorbed. Also, the model shows that celiac disease damages the epithelial cells of villi. The epithelial cell layer is important for the diffusion of nutrients to the capillaries. Without a healthy epithelial cell later, fewer nutrients may be absorbed, and the body may not have enough energy to perform its functions.

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Read 2 more answers
In this example, we used lotka-volterra equations to model populations of rabbits and wolves. let's modify those equations as fo
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Answer:

Wolves absence would lead the rabbit population to become stable at 5,000.

Explanation:

Step 1. Concept

If there is a missing variable that should be in the system, set that particular variable to zero and make the necessary conclusion.

Step 2. Given,

dR/dt = 0.08R(1 - 000.2R) - 0.001RW

dW/dt = −0.02W + 0.00002RW

Step 3. Calculation

The transformed equations of populations of rabbit and wolves will be

dR/dt = 0.08R(1 - 000.2R) - 0.001RW

dW/dt = −0.02W + 0.00002RW

Let's check the rabbit population in the absence of wolves(W) to 0

Thus,

Differential equation dR/dt

dR/dt = 0.08R(1 - 000.2R) - 0.001RW

Take W to equal to O

dR/dt = 0.08R(1 - 000.2R) - 0.001R(0)

dR/dt = 0.08R(1 - 000.2R)

When,

dR/dt = 0 we have R = 0 or R = 5,000

This,

R = 5,000 becomes the equilibrium point in the absence of wolves

Then,

0 < R < 5,000, dR/dt > 0

For R, let's estimate a value rise of the rabbit population to 5,000

Then,

R > 5,000, dR/dt < 0

Judging from the value if R, we infer a deduction in the rabbit population by 5,000

Thus,

We can conclude that wolves absence would lead the rabbit population to become stable at 5,000.

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