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Shtirlitz [24]
2 years ago
6

If Kevin makes c toys in m minutes, how many toys can he make per hour?

Mathematics
1 answer:
mojhsa [17]2 years ago
8 0

Answer:

The number of toys that Kevin can make per hour is equal to 60\frac{c}{m}\ toys

Step-by-step explanation:

we know that

Kevin makes c toys in m minutes

Remember that

1 hour=60 minutes

so

Using proportion find out how many toys can be make in 60 minutes (one hour)

Let

x -----> the  number of toys that Kevin can make per hour

so

\frac{c}{m}=\frac{x}{60}\\ \\x=60\frac{c}{m}\ toys

therefore

The number of toys that Kevin can make per hour is equal to 60\frac{c}{m}\ toys

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(iii) Find the smallest whole number h such that<br>4704/h<br>is a cube number.<br>​
yan [13]

Answer:

h=588

Step-by-step explanation:

Given the fraction \dfrac{4,704}{h}

Consider its numerator and factor it:

4,704=2^5\cdot 3\cdot 7^2

You cann not take the cube root from 3, 7^2, 2^5, you can only take the cube root from 2^3, then the smallest whole number h such that \dfrac{4,704}{h} is a cube number is

h=2^2\cdot 3\cdot 7^2=4\cdot 3\cdot 49=588

When h=588,

\dfrac{4,704}{588}=8=2^3

6 0
2 years ago
Write the verbal sentence as an equation. let y represent the number
viktelen [127]

Answer:

Marcus is picking songs to play during a slideshow. The songs are each 3\dfrac123  

2

1

​  

3, start fraction, 1, divided by, 2, end fraction minutes long. The slideshow is 31\dfrac1231  

2

1

​  

31, start fraction, 1, divided by, 2, end fraction minutes long.

Step-by-step explanation:

8 0
2 years ago
After a number of complaints about its tech assistance, a computer manufacturer examined samples of calls to determine the frequ
icang [17]

Answer:

a) Upper Control Limit = 0.10

   Lower Control Limit = 0.01

b) The tech assistance process is stable and in control.

Step-by-step explanation:

Given - After a number of complaints about its tech assistance, a

            computer manufacturer examined samples of calls to determine

            the frequency of wrong advice given to callers. Each sample

            consisted of 100 calls.

SAMPLE             1   2   3   4   5   6   7   8   9  10 11 12 13 14 15 16

Number of errors 5  3   5   7   4   6   8   4   5    9   3   4   5   6   6   7

To find - a. Determine 95 percent limits.

              b. Is the tech assistance process stable (i.e., in control)

Proof -

z = 95% confidence interval

  = 1.96

⇒z = 1.96

Proportion of defects,P = total defectives/total observations

                                     = 0.0544

⇒P = 0.0544

Now,

Q = 1-P

   = 0.9456

⇒Q = 0.9456

Now,

Average sample size, N = 100

Standard deviation = \sqrt{\frac{P.Q}{N} }

                             = 0.0227

Now,

Upper Control Limit = P + z(Standard deviation)

        = 0.0988

⇒Upper Control Limit = 0.0988 ≈ 0.10

And

Lower Control Limit = P - z(Standard deviation )

       = 0.0099

⇒Lower Control Limit = 0.0099 ≈ 0.01

∴ we get

Upper Control Limit = 0.10

Lower Control Limit = 0.01

b.)

Now,

it is clear that the fraction defective values are wit in upper an lower control limits.

So, The tech assistance process is stable and in control.

5 0
2 years ago
Estimate the indicated probability by using normal distribution as an approximation to the binomial distribution. Estimate P(6)
lianna [129]

Answer:

P(6) = 0.6217

Step-by-step explanation:

To find P(6), which is the probability of getting a 6 or less, we will need to first calculate two things: the mean of the sample (also known as the "expected value") and the standard deviation of the sample.  

Mean = np

Here, "n" is the sample size and "p" is the probability of the outcome of interest, which could be getting a heads when a tossing a coin, for instanc

So, Mean = n × p = (18) ×(0.30) = 5.4

Next we we will find the standard deviation:

Standard Deviation = \sqrt{npq}

n = 18  and  p = 0.3   "q" is simply the probability of the other possible outcome (maybe getting a tails when flipping a coin), so   q = 1 - p

Standard Deviation =\sqrt{npq} = \sqrt{(18)(0.3)(0.7)}  

                                                            = 1.944

Now calculate the Z score for 6 successes.  

Z = ( of successes we're interested in - Mean) ÷ (Standard Deviation)

=(6-5.4)  ÷ (1.944) = 0.309

we have our Z-score, we look on the normal distribution and find the area of the curve to the left of a Z value of 0.309.  This is basically adding up all of the possibilities for getting less than or equal to 6 successes.  So, we get 0.6217.

5 0
2 years ago
Cristine's middle school has a total of 900 students and 45 teachers. The local high school has 110 teachers and a student-teach
frozen [14]
Write and solve an equation of ratios:

900 students      45 teachers         
------------------  = -----------------  
          x               110 teachers     

Cross multiplying, we get (900)(110) / 45, or

                                                                 
so x = # of students in the high school = 2200   (answer)
                                                                    
8 0
2 years ago
Read 2 more answers
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