Answer:

Step-by-step explanation:
<u>Area Of A Cube
</u>
Suppose a cube with side length s, the area of one side is

Since the cube has 6 sides, the total area is

But if we have the area, we can solve the above formula for s to get


We have two different cubes with areas 1,200 square inches and 768 square inches. Let's compute their side lengths




The difference between them is

The side of the cube with area 1,200 square inches is
longer then the side of the cube with area 768 square inches
Answer:


Step-by-step explanation:
The question is 
<em>We let
, so the equation becomes:</em>

Where 
Putting it in the quadratic formula, we have:
<u>Quadratic formula:</u> 
Substituting we have: 
<em>We let
, so x is:</em>
<em>
</em>
<em>and</em>
<em>
</em>
The solutions of the equation is
(rounded to 2 decimal places), and
(rounded to 2 decimal places)
since its an isoscelies trangle, they probably wanted you to do base times height
make a 71-91/2-x x triangle
where x is the height of the triangle to the base 91 and 71 is the hypothenuse
and then do bh/2
or
use heron's formula
s= 71+91/2
area= 
have fun solving that
Answer:
(negative 7 x + 4)(negative 7 x minus 4)
Step-by-step explanation:
Consider two real numbers a and b. A difference of squares involving a and b is usually given as;

The difference of the two squares above can be factored to yield;

This implies that in order to have the difference of squares we must have a product involving the difference and the sum of the numbers.
The expression;
(negative 7 x + 4)(negative 7 x minus 4) can also be written as ( 4 - 7x) ( -4 - 7x)
( 4 - 7x) ( -4 - 7x) = ( 4 - 7x) (-1( 4 + 7x)) = -1 *( 4 - 7x) ( 4 + 7x)
Expanding the last expression yields;
-1 (16 + 28x -28x - 49x^2) = -1 (16 - 49x^2) = 49x^2 - 16 which is in deed a difference of squares
The solution to the problem is as follows:
<span>cos2A - cos4A = -2 sin(6A/2).sin(-2A/2) = +2 sin(3A).sinA
and
sin4A - sin2A = 2 cos(6A/2).sin(2A/2) = 2 cos(3A).sinA
Hence RHS = (cos(2A)-cos(4A))/ (sin(4A)- Sin(2A)) = sin 3A / cos 3A = tan 3A = LHS
</span>
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