Probability that gear 1 will fail = 5/100 (upto 10 years)
and 8/100 (after 10 years)
Probability that both will fail = 5/100 * 8/100
= 40/10000
= 0.4 %
Answer:
We have the functions:
f(x) = IxI + 1
g(x) = 1/x^3.
Now, we know that the composite functions do not permute.
How we can prove this?
First, two composite functions are commutative if:
f(g(x)) = g(f(x))
Well, you could use brute force (just replace the values and see if the composite functions are commutative or not)
But i will use a more elegant way.
We can notice two things:
g(x) has a discontinuity at x = 0.
so:
f(g(x)) = I 1/x^3 I + 1
still has a discontinuty at x = 0, but:
g(f(x)) = 1/( IxI + 1)^3
here the denominator is IxI + 1, is never equal to zero.
So now we do not have a discontinuity.
Then the composite functions can not be commutative.
Substract 3 from the total and divide it with 2
one of them is 5 and the other one is 8.
Answer:
(A)
Step-by-step explanation:
Given the equations:

Substitution simply means replacing the variable y in the second equation with its equivalent x+3 from the first equation.
Substitution of y into
gives us:

The correct option is A.
Answer:
The margin of error for a 95% confidence interval estimate for the population mean using the Student's t-distribution is of 6.22 ounces.
Step-by-step explanation:
The first step to solve this problem is finding how many degrees of freedom, we have. This is the sample size subtracted by 1. So
df = 23 - 1 = 22
95% confidence interval
Now, we have to find a value of T, which is found looking at the t table, with 22 degrees of freedom(y-axis) and a confidence level of
. So we have T = 2.0739
The margin of error is:
M = T*s
In which s is the standard deviation of the sample.
In this question:
s = 3.
Then
M = 2.0739*3 = 6.22
The margin of error for a 95% confidence interval estimate for the population mean using the Student's t-distribution is of 6.22 ounces.