Question

Solve the system of equations by substitution. x + y = A system of equations. StartFraction 3 over 8 EndFraction x plus StartFraction one-third EndFraction y equals StartFractions 17 over 24 EndFraction. x + 7y = 8

Answer 1

Answer:

$x=1\\\\y=1$

Step-by-step explanation:

Given the following system of equations:

$\left \{ {{\frac{3}{8}x+\frac{1}{3}y=\frac{17}{24} } \atop {x + 7y = 8}} \right.$

The procedure to solve using the Substitution method, is:

- Solve for "x" from the second equation:

$x + 7y = 8\\\\x=8-7y$

- Substitute it into the first equation and solve for "y":

$\frac{3}{8}(8-7y)+\frac{1}{3}y=\frac{17}{24}\\\\3-\frac{21}{8}y+\frac{1}{3}y=\frac{17}{24}\\\\-\frac{55}{24}y=-\frac{55}{24}\\\\y=1$

- Substitute these value into the second equation of the system of solve for "x":

$x + 7(1)= 8\\\\x=8-7\\\\x=1$

Answer 2

Answer: 1 for both

Step-by-step explanation: