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galina1969 [7]
2 years ago
13

Pregnancy length (in days) has a normal probability distribution with a mean of 266 days and a standard deviation of 16 days. Wh

at is the length of the pregnancy that marks the start of the 25th percentile? Enter a number rounded to two decimal places. Do not enter the units.
Mathematics
1 answer:
Oxana [17]2 years ago
4 0

Answer:

264.20

Step-by-step explanation:

Let X be the pregnancy length (in days)

Then X is N(266,16)

We can convert X to Z by

\frac{x-266}{16}

Z=\frac{x-266}{16} is N(0,1)

25th percentile for Z is

-0.675

Convert back to x score

x=-0.675(16)+275\\X =264.20

25th percentile is 264.20

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A video game randomly chooses your car color and type. The probability of getting a red car is 0.20, and the probability of gett
pishuonlain [190]

Answer: Option 'D' is correct.

Step-by-step explanation:

Since we have given that

Event A: You get a red car

and

P(A)=0.20

Similarly,

Event B: You get a convertible

and

P(B)=0.40

So, if A and B are independent , then they must satisfy,

P(A).P(B)=P(A\cap B)

So,

P(A\cap B)=0.4\times 0.2=0.08

Hence, Option 'D' is correct, which states that the probability of getting a red convertible is 0.08.

7 0
2 years ago
Students are asked to memorize a list of 100 words. The students are given periodic quizzes to see how many words they have memo
Yuri [45]

Answer:

C. dL/dt=k(100−L)

Step-by-step explanation:

The rate of change of the number of words memorized is proportional to the number of words left to be memorized.

The rate of change is dL/dt.

The rate is a constant k. Since the rate is proportional to the number of words left to be memorized, and the initial number of words is 100, k has to be multiplied by (100-L).

So the correct answer is:

C. dL/dt=k(100−L)

6 0
2 years ago
Tanya walked for 171717 minutes from her home to a friend that lives 1.51.51, point, 5 kilometers away. d(t)d(t)d, left parenthe
Butoxors [25]

Correct question is;

Tanya walked for 17 minutes from her home to a friend that lives 1.5 kilometers away. D(t) models Tanyas remaining distance to walk in kilometers, t minutes since she left home. What number type is more appropriate for the domain of d?

Answer:

0 ≤ t ≤ 17 ; (0, 17)

Step-by-step explanation:

We are told that she has walked for 17 minutes from her home to a friend that lives 1.5 kilometers away.

Now, we want to find the domain of numbers that shows her remaining distance.

Since she spent 17 minutes, then it means in modeling remaining distance it could be from 0 to 17 minutes as the case may be. Thus, the domain can be written as;

0 ≤ t ≤ 17 ; (0, 17)

6 0
2 years ago
Read 2 more answers
Find the area of the kite
Thepotemich [5.8K]

Step-by-step answer:

Area of a kite is half of the product of the diagonals.

The length of diagonal in the x-direction is 4+5 = 9

The length of diagonal in the y-direction is 4+4 = 8

Therefore

Area of kite = 8*9/2 = 36 units.

3 0
2 years ago
Read 2 more answers
The size of fish is very important to commercial fishing. A study conducted in 2012 found the length of Atlantic cod caught in n
devlian [24]

Answer:

The length of the longest 15% of Atlantic cod in this area is 53.79cm, roundeed to 2 decimal places.

Step-by-step explanation:

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by

Z = \frac{X - \mu}{\sigma}

After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X.

In this problem, we have that:

A study conducted in 2012 found the length of Atlantic cod caught in nets in Karlskrona to have a mean of 49.9 cm and a standard deviation of 3.74 cm, so \mu = 49.9, \sigma = 3.74.

What is the length in cm of the longest 15% of Atlantic cod in this area?

We have to find the value of X for the value of Z that has a pvalue of 0.85.

Looking at the zscore table, we have that Z = 1.04 has a pvalue of 0.8508. So, we have to find the value of X when Z = 1.04, \mu = 49.9, \sigma = 3.74.

So

Z = \frac{X - \mu}{\sigma}

1.04 = \frac{X - 49.9}{3.74}

X - 49.9 = 3.8896

X = 53.7896

The length of the longest 15% of Atlantic cod in this area is 53.79cm, roundeed to 2 decimal places.

8 0
2 years ago
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