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bija089 [108]
2 years ago
11

Do acidic conditions deactivate amylase?

Biology
2 answers:
Kitty [74]2 years ago
6 0
Yeah!! As it acts in slightly acidic medium i.e., of pH 6.8 so, acidic conditions deactivate amylase enzyme...
Evgen [1.6K]2 years ago
3 0

Answer:

The correct answer would be "yes, acidic environment decreases or deactivates the amylase enzyme".

Amylase refers to the class of enzymes which are involved in the hydrolysis of sugars (polysaccharides).  

For example, salivary amylase and pancreatic amylase hydrolyze the starch into di and trisaccharides.

In addition, the amylase present in the human physiology (alpha amylase) has the optimum pH of 6.7-7.0 and thus, this amylase would get deactivated in acidic or low pH conditions.

This is why the pH of the intestine is slightly basic which complements the functioning of the pancreatic amylase.

The acidic medium can cause the denaturation of the enzyme and thus, results in the deactivation of the enzyme.

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Check your understanding
wel

The fraction of offspring with black coat color and straight fur is 9/16.

Explanation:

Information given:

black coat colour and straight fur - dominant genotype BBCC, BbCc

yellow coat colour and curly fur - recessive genotype  bbcc

Both the traits are independently assorted. The fur colour and fur type is not present on the same chromosome and are not sex linked.

The genotype of the parents are:

BbCc X BbCc

Punnet square shows:

          BC           Bc          bC        bc

BC  BBCC   BBCc        BbCC   BbCc

Bc  BBCc   BBcc          BbCc    Bbcc

bC BbCC    BbCc         bbCC   bbCc

bc  BbCc      Bbcc         bbCc    bbcc

9 BLACK STRAIGHT

 3 BLACK CURLY

 3 YELLOW STRAIGHT

  1  YELLOW CURLY

9/16 is the fraction of progeny to be black coat colour and straight fur.

5 0
1 year ago
If 32 packed volume units of cells are separated from 46 volume units of plasma from a blood sample, the haematocrit is _______
nordsb [41]

Answer:

If 32 packed volume units of cells are separated from 46 volume units of plasma from a blood sample, the hematocrit is <u>41,02%</u> percent. The hematocrit value is <u>within the normal</u> range.

Explanation:

Hello!

Hematocrit (or packed cell volume -PCV-)is defined as the percentage of red blood cells (vol%) in a blood sample. One common method of determining it is by centrifuging a heparinized blood sample in a capillary tube at 10 000 RPM for five minutes. This separates the blood sample in two layers, formed elements (RBC and WBC) and Plasma.

The length of the layers is directly measured from the tube and represents the volume of packed cells and plasma. Since the number of white cells is negligible compared to the number of red cells, the formed elements are considered to represent the red blood cells.

The hematocrit can be calculated as the volume of packed cells divided by the total volume of the blood sample.

\frac{PCV}{TOTAL(pcv+plasma} * 100

<u>In the question:</u>

\frac{32}{32+46} * 100 = \frac{32}{78} * 100 = 41,02%

In humans the normal hematocrit range is 40,7% to 50,3% for men and 36,1% to 44,3%. Taking these reference values into consideration, this sample is within the normal range.

I hope you have a SUPER day!

4 0
2 years ago
When earthworms bring fine rock particles to the surface what type of weathering is that??
SIZIF [17.4K]
When earth worms bring fine rocks to particles they do it in mechanical weathering

5 0
1 year ago
Increasing the substrate concentration in an enzymatic reaction could overcome which of the following?
borishaifa [10]
Answer to this question is a
7 0
1 year ago
student prepared a test tube containing yeast, glucose, and water. After 24 hours, the test tube was analyzed for the presence o
expeople1 [14]

Answer:

In the presence of oxygen, respiration of yeast produces carbon dioxide and water. In the absence of oxygen, respiration of yeast produces carbon dioxide and alcohol.

Under the assumption that the yeast has insufficient exposure to oxygen in the surrounding air in the testtube, alcohol and carbon dioxide would be expected to be found in the test tube

5 0
2 years ago
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