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Nonamiya [84]
2 years ago
13

Polar, Ferrell, and Hadley cells are ____________ that circulate ____________ around the globe. These cells also create ________

____ that move over Earth’s surface. Where the cells meet, ____________ develop, which are fast moving corridors of air that influence weather patterns.
Geography
1 answer:
Kamila [148]2 years ago
8 0

Answer:

  • convection cells
  • moisture and heat
  • winds
  • jet streams

Explanation:

While the Polar and Hadley cells are strictly closed-loop convection cells, the Ferrell cells are not completely closed. Together these three types of cells represent atmosphere circulation and are responsible for distributing heat and moisture around the planet. Warm air is transported from the Tropics to the polar regions and cold air is pushed southward.

The Polar cell is made up of frigid air due to low solar heating and is therefore denser. the Hadley cells converge at the equator to form the Intertropical Convergence Zone. the Mid-latitude Ferrell cells are the most unstable and experience the most windy conditions. Their exact location wanders throughout the course of the  year.

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Answer:

a) d = 35.0143 Km

t = 188 days

v = 7.76*10⁻³ Km/h

b) d = 28.6356 Km

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Explanation:

a. From where the shoes spilled (48°N, 161°W) to where they first made landfall (49°N, 126°W), how many kilometers did they travel?  

We can use the equation

d = √(∆N²+∆W²)

⇒   d = √((49-48)²+(126-161)²) = 35.0143 Km

How many days did they take to travel that distance? (You can use November 30 as the date found).  

From May 27, 1990 to November 30, 1990 we have

t = 5 days + (30 days/month)*(3 months) + (31 days/month)*(3 months) = 188 days

⇒   t = 188 days = (188 days)*(24 hours/day) = 4512 hours

What was their rate of travel in kilometers per hour?  

We use the equation

v = d/t   ⇒   v =  35.0143 Km/ 4512 h

⇒   v = 7.76*10⁻³ Km/h

b. From where the shoes spilled (48°N, 161°W) to where they were found in 1996 (54°N, 133°W), how many kilometers did they travel?  

We can use the equation

d = √(∆N²+∆W²)

⇒   d = √((54-48)²+(133-161)²) = 28.6356 Km

How many days did they take to travel that distance (use April 30 as the date found)?  

From May 27, 1990 to April 30, 1996 we have

t = 5 days + (30 days/month)*(4 months) + (31 days/month)*(6 months) + 29 days + (365 days/ year)*(4 years)+ (366 days/ year)*(1 year)= 2165 days

⇒   t = 2165 days = (2165 days)*(24 hours/day) = 51960 hours

What was their rate of travel in kilometers per hour?

We use the equation

v = d/t   ⇒   v =  28.6356 Km/ 51960 h

⇒   v = 5.51*10-4 Km/h

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