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slava [35]
2 years ago
7

Refer to the exhibit. Which two network addresses can be assigned to the network containing 10 hosts? Your answers should waste

the fewest addresses, not reuse addresses that are already assigned, and stay within the 10.18.10.0/24 range of addresses. (Choose two.)
A. 10.18.10.200/28
B. 10.18.10.208/28
C. 10.18.10.224/28
D. 10.18.10.200/27
E. 10.18.10.224/27
Computers and Technology
1 answer:
ololo11 [35]2 years ago
4 0

As result as follows these two network addresses can be assigned to the network containing 10 hosts:

B. 10.18.10.208/28

C. 10.18.10.224/28

<u>Explanation:</u>

Since 10.18.10.0/24 depends on subnet also.  10.18.10.0 To 10.18.10.63 is taken to leftmost network address. Since it is 4 host bits, it required to accommodate 10 hosts.  And it marks to be in end with /28.

And more over 10.18.10.200/28 should be invalid network number. Moreover other one ends with /27 it is invalid to this specific ranges of tcpip address.

Other 10.18.10.200/27 or 10.18.10.224/27 is falls in invalid range, because it ends with /27

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Write a loop that subtracts 1 from each element in lowerScores. If the element was already 0 or negative, assign 0 to the elemen
Xelga [282]

Answer:

The JAVA program to implement for loop for given scenario is shown below.

public class MyProgram {

   public static void main(String args[]) {    

     int len = 5;

     int[] lowerScores = new int[len];      

     lowerScores[0] = 5;

     lowerScores[1] = 0;

     lowerScores[2] = 2;

     lowerScores[3] = -3;      

     System.out.println("The original elements of array are ");

     for(int i=0; i<len; i++)

     {

         System.out.print(lowerScores[i]+" ");

     }      

     System.out.println();

     System.out.println("The modified elements of array are ");

     for(int i=0; i<len; i++)

     {

         // if element is 0 or negative, 0 is assigned to this index

         if(lowerScores[i] <= 0)

           lowerScores[i] = 0;

       // 1 is subtracted from every non zero and positive element

         else

           lowerScores[i] = lowerScores[i] - 1;

           

       System.out.print(lowerScores[i]+" ");

     }

   }

}

OUTPUT

The original elements of array are  

5 0 2 -3 0  

The modified elements of array are  

4 0 1 0 0

Explanation:

The integer array is declared as shown.

int[] lowerScores = new int[len];

The length of the array is given by integer variable len. As per the question, we have taken four elements and size of 5 for the given array.

int len = 5;

The elements of the array are initialized inside the program with the elements given in the question.

lowerScores[0] = 5;

      lowerScores[1] = 0;

The values of the array can be changed to test the program. Also, the size of the array can be changed for testing.

As per the given scenario, if the element is greater than zero, 1 is subtracted from this element. For elements less than or equal to zero, that particular element is assigned the value of 0.

The given program implements if else statement inside for loop for this purpose.

for(int i=0; i<len; i++)

     {

         // if element is 0 or negative, 0 is assigned to this index

         if(lowerScores[i] <= 0)

           lowerScores[i] = 0;

       // 1 is subtracted from every non zero and positive element

         else

           lowerScores[i] = lowerScores[i] - 1;

     }  

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Answer:

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The most common combination of these elements is the windows, icons, menus and pointer paradigm (WIMP) . GUIs are used in mobile devices, gaming devices, smartphones, MP3 players etc.

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Answer:

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Explanation:

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Also, yourNum is decremented by 1 and becomes 3

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