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NARA [144]
2 years ago
11

The saltation of sand involves ________.

Geography
1 answer:
Alenkinab [10]2 years ago
5 0

Answer:

b. grains traveling short distances (approximately 1 m) in the air

Explanation:

Wind is a very efficient erosion agent, and its action, particularly in areas of arid, semi-arid and desert climates, is responsible for transporting and depositing large volumes of sediments with the development of a typical wind landscape.

The diameter of the sand grains transported by the wind averages between 0.15 and 0.30 mm, with some fine grains up to 0.006 mm, all particles smaller than 0.006 mm are classified as dust. A grain the size of the dust is carried high in the air and a grain the size of the sand is carried forward near the ground by jumping (see figure 1). As the particle size increases, the attraction of gravity and air resistance also increase.

The soil surface particles are transported by the wind in three ways:

- By drag: the thickest particles (500 - 2000 microns).

- By saltation: medium particles (100-500 microns).

- In suspension: the smallest and lightest particles (<100 microns, 0.2 mm).

The <u>saltation</u> moves the particles by small jumps, in the direction of origin of the wind and normally does not remove them more than 1 centimeter above the ground. An individual grain rolls forward driven by the wind, until it bounces with a second grain. Once in the air, it is carried forward by the wind and drawn to the ground by gravity. It follows a parabolic path falling on the ground with an angle between 10º and 16º, and usually traveling short distances.

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5. How fast did the shoes travel? (4 points) a. From where the shoes spilled (48°N, 161°W) to where they first made landfall (49
Leto [7]

Answer:

a) d = 35.0143 Km

t = 188 days

v = 7.76*10⁻³ Km/h

b) d = 28.6356 Km

t = 2165 days

v = 5.51*10-4 Km/h

Explanation:

a. From where the shoes spilled (48°N, 161°W) to where they first made landfall (49°N, 126°W), how many kilometers did they travel?  

We can use the equation

d = √(∆N²+∆W²)

⇒   d = √((49-48)²+(126-161)²) = 35.0143 Km

How many days did they take to travel that distance? (You can use November 30 as the date found).  

From May 27, 1990 to November 30, 1990 we have

t = 5 days + (30 days/month)*(3 months) + (31 days/month)*(3 months) = 188 days

⇒   t = 188 days = (188 days)*(24 hours/day) = 4512 hours

What was their rate of travel in kilometers per hour?  

We use the equation

v = d/t   ⇒   v =  35.0143 Km/ 4512 h

⇒   v = 7.76*10⁻³ Km/h

b. From where the shoes spilled (48°N, 161°W) to where they were found in 1996 (54°N, 133°W), how many kilometers did they travel?  

We can use the equation

d = √(∆N²+∆W²)

⇒   d = √((54-48)²+(133-161)²) = 28.6356 Km

How many days did they take to travel that distance (use April 30 as the date found)?  

From May 27, 1990 to April 30, 1996 we have

t = 5 days + (30 days/month)*(4 months) + (31 days/month)*(6 months) + 29 days + (365 days/ year)*(4 years)+ (366 days/ year)*(1 year)= 2165 days

⇒   t = 2165 days = (2165 days)*(24 hours/day) = 51960 hours

What was their rate of travel in kilometers per hour?

We use the equation

v = d/t   ⇒   v =  28.6356 Km/ 51960 h

⇒   v = 5.51*10-4 Km/h

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2 years ago
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