What is probablity, and how would I be able to find? (Could you also show an example)

Factor the following polynomial completely. -x2 y2 + x4 + 4y 2 - 4x2

Rufina [12.5K]

Step by step he sir

8 0

1 year ago

A company purchased a delivery van for $28,000 with a salvage value of $3,000 on September 1, Year 1. It has an estimated useful

Tems11 [23]

Answer:

Depreciation till December 31, Year 1 will be equal to 1,250$

Step-by-step explanation:

Purchasing Cost = 28,000$

Salvage Value = 3,000$

Total Depreciation:

Total Depreciation over 5 years (60 Months) = Purchasing Cost - Salvage Value

Total Depreciation over 5 years (60 Months) = 28,000 - 3,000

Total Depreciation over 5 years (60 Months) = 25,000$

Monthly Depreciation:

Using the unity method we have monthly depreciation by dividing the total depreciation by the total no. of months as below:

Total Depreciation over a single month =25,000/60

Total Depreciation over a single month = 416.67$ (Monthly Depreciation)

Depreciation till December 31, Year 1

As from September 1, Year 1 to December 31, Year 1, its been 3 months therefore total depreciation will be = 3 * Monthly Depreciation

Depreciation till December 31, Year 1 = 3 * 416.67

Depreciation till December 31, Year 1 = 1,250$

4 0

1 year ago

2 inches 3 inches Pivot. If 60 lbs. of force must be applied to the valve for it to open, how much upward force must push rod X

tresset_1 [31]

We can solve this problem by stating that the summation of momentums must be zero. That is, the momentum at one end of the pivot must be equal to the momentum at the other end.

Momentum 1 = Momentum 2

Since Momentum is the product of Force and Distance, and with this rule created, we can say that:

F1 * d1 = F2 * d2

Where,

F1 = 60 lbs

d1 = 2 inches from the pivot

F2 = unknown X

d2 = 3 inches from the pivot

Substituting to the equation to find for F2:

60 lbs * 2 inches = F2 * 3 inches

F2 = 40 lbs

Therefore 40 lbs of upward force must be pushed to open the valve.

Answer: B

3 0

1 year ago

Which statements about the figure are true? Select two options.

harina [27]

Complete Question

The circle is inscribed in triangle PRT. A circle is inscribed in triangle P R T. Points Q, S, and U of the circle are on the sides of the triangle. Point Q is on side P R, point S is on side R T, and point U is on side P T. The length of R S is 5, the length of P U is 8, and the length of U T is 6. Which statements about the figure are true?

Answer:

(B)TU ≅ TS

(D)The length of line segment PR is 13 units.

Step-by-step explanation:

The diagram of the question is drawn for more understanding,

The theorem applied to this problem is that of tangents. All tangents drawn to a circle from the same point are equal.

Therefore:

|PQ|=|PU|=8 Units

|ST|=|UT| =6 Units

|RS|=|RQ|=5 Units

(b)From the above, TU ≅ TS

(d)Line Segment |PR|=|PQ|+|QR|=8+5=`13 Units

6 0

2 years ago

Read 2 more answers

What’s the answer? Because am having a hard time with this math problem.

Studentka2010 [4]

9514 1404 393

Answer:

34.5 square meters

Step-by-step explanation:

We assume you want to find the area of the shaded region. (The actual question is not visible here.)

The area of the triangle (including the rectangle) is given by the formula ...

A = 1/2bh

The figure shows the base of the triangle is 11 m, and the height is 1+5+3 = 9 m. So, the triangle area is ...

A = (1/2)(11 m)(9 m) = 49.5 m^2

The rectangle area is the product of its length and width:

A = LW

The figure shows the rectangle is 5 m high and 3 m wide, so its area is ...

A = (5 m)(3 m) = 15 m^2

The shaded area is the difference between the triangle area and the rectangle area:

shaded area = 49.5 m^2 - 15 m^2 = 34.5 m^2

The shaded region has an area of 34.5 square meters.

7 0

1 year ago