Answer:
Genetic diversity: Some individuals in a population of wild rabbits are resistant to a new disease.
Ecosystem diversity: If the population of wild rabbits decreases, a bobcat can switch its diet to squirrels or woodchucks.
Species diversity: Populations of wild rabbits from a forest and from a neighboring meadow can interbreed, which increases variation.
Biodiversity of an ecosystem is usually explored by three diversities which are responsible for ecosystem stability they are : genetic diversity, ecosystem diversity and species diversity.
Genetic diversity is the variety of genes within a population of species. Each species consists of individuals bearing different genetic composition. Some individuals in a population of wild rabbits are resistant to a new disease because they exhibit genetic diversity within the population as a consequence some individuals exhibit genes which protect them against new disease.
Species diversity is the variety of species within an ecosystem. Populations of wild rabbits from a forest and from a neighboring meadow can interbreed, which increases variation is an example of species diversity. The wild rabbits from a forest and a neighboring meadow are two species living in an ecosystem stating the diversity of species in an ecosystem.
Ecosystem diversity is the variety of ecosystems in a given region.If the population of wild rabbits decreases, a bobcat can switch its diet to squirrels or woodchucks is an example of ecosystem diversity because in an ecosystem there is interaction of organisms as predator prey relationship. This example is also relating with predator prey relationships in an ecosystem.
Answer:
This mutation will produce a conformational change capable of maintaining the receptor continuously in its activated mode
Explanation:
G proteins are inactive when guanosine diphosphate (GDP) is bound, while they are active when guanosine triphosphate (GTP) is bound
Answer:
Explanation:
Narrow sense heritability - h2
selection differential - S
Selection differential is calculated from the difference between the population average and the parental population.
Breeder's equation:
Response to selection - R = h2S
Mean milk production of 10% cows for experiment = 8.9L/hr
Mean milk production of parental population = 5.1L/hr
Selection differential S= 8.9 - 5.1 = 3.8 L/hr
Response to selection = 0.587 × 3.8 = 2.23
