To determine the number of photons emitted per second, we need data on the total power of the system and the total energy of the photons. We determine the power by multiplying the total area to the intensity of the sunlight given. We do as follows:

Power = 0.50 kW / m^2 ( π (0.001^2)) = 1.57x10^-6 kW = 1.57x10^-3 W

The energy of the visible light can be calculated from the expression:

Energy = hc / wavelength

where h is the planck's constant and c is the speed of light

Energy = (6.63 x 10^-34) (3 x 10^8) / 550 x 10^-9
Energy = 3.62 x 10^-19 J

Number of photons per second =  1.57x10^-3 J/s / 3.62 x 10^-19 J
Number of photons per second = 4.34x10^15 

Because of gravity and friction. 

Refer to the figure shown below.

From the geometry,
y = 100 - (44 - 3) = 59 ft
From the Pythagorean theorem,
x² = 100² - 59² = 6519
x = 8007403 ft

Calculate the central angle, θ.
cos θ = 59/100 = 0.59
θ = 53.84° = 0.9397 radians

Calculate the arc length pq.
S = pq = 0.9394*100 = 93.94 ft

Calculate the angular velocity.
ω = (0.9397 radians)/(5 s) = 0.188 rad/s

Calculate the tangential velocity.
v = (100 ft)*(0.188 rad/s) = 18.8 ft/s

Calculate the time for 1 revolution.
T = (2π rad)/(0.188 rad/s) = 33.4 s

Answers:
The angular speed is  0.188 rad/s
The tangential speed is 18.8 ft/s
The time for one revolution is 33.4 s

Answer:

Ecu/Eag = 0.46

Explanation:

E = PI/A

Ecu = Pcu × I/A

Pcu = 1.72×10^-8 ohm-meter

r = 0.8 mm = 0.8/1000 = 8×10^-4 m

A = πr^2 = π×(8×10^-4)^2 = 6.4×10^-7π

Ecu = 1.72×10^-8I/6.4×10^-7π = 0.026875I/1

Eag = Pag × I/A

Pag = 1.47×10^-8 ohm-meter

r = 0.5 mm = 0.5/1000 = 5×10^-4 m

A = πr^2 = π × (5×10^-4)^2 = 2.5×10^-7π

Eag = 1.47×10^-8I/2.5×10^-7π = 0.0588I/π

Ecu/Eag = 0.026875I/π × π/0.0588I = 0.46