Answer:
-0.01 mm
Explanation:
We are given that
The value of one division of vernier scale =0.5 mm
The value of one main scale division=0.49 mm
We have to find the value of least count of the instrument in mm.
We know that
Leas count of vernier caliper=1 main scale division-1 vernier scale division
Least count of vernier caliper=0.49-0.50=-0.01 mm
Hence, the least count of the instrument=-0.01 mm
Answer: -0.01 mm
Answer:
The excess charge is 
Explanation:
From the question we are told that
The diameter is 
The potential of the surface is 
The radius of the sphere is
substituting values
The potential on the surface is mathematically represented as
Where k is coulomb's constant with value 
given from the question that there is no other charge the Q is the excess charge
Thus
substituting values
Answer:
Volume = 6.5 x 10¹⁸ cm³
Explanation:
The volume of an object is the space enclosed by three dimensional surfaces of the object. The volume of an object can be given in terms of area and height. The formula of the volume of an object in terms of area and height is given as follows:
Volume = Area x Height
for Pacific Ocean we have the following data:
Area = (166241700 km²)(10⁵ cm/1 km) = 1.66 x 10¹³ cm²
Height = Depth = (3940 m)(10² cm/1 m) = 3.94 x 10⁵ cm
Therefore, using these values, we get:
Volume = (1.66 x 10¹³ cm²)(3.94 x 10⁵ cm)
<u>Volume = 6.5 x 10¹⁸ cm³</u>
Answer:
3.3kg
Explanation:
Given parameters:
Spring constant = 400N/m
Extension = 8cm = 0.08m
Unknown:
Amount of mass the spring is supporting = ?
Solution:
To solve this problem:
F = kE
F is the force
k is the spring constant
E is the extension
So;
F = 400 x 0.08 = 32N
Mass;
Force = mass x acceleration due to gravity
32 = mass x 9.8
Mass = 3.3kg
