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Semenov [28]
2 years ago
13

Isabella's manager has asked her to write up a _____ that describes their company's interest in developing a custom software sol

ution for processing orders and asks vendors to estimate the cost and time needed to create the software.
Computers and Technology
1 answer:
kakasveta [241]2 years ago
6 0

Answer:

Request for information (RFI)

Explanation:

Request for Information is a business process document that contains information about an organization's capability to deliver solutions to a potential client. The RFI document will contain information that will help for decision making by clients. Other similar business documents in this line are Request for tender (RFT), request for quotation (RFQ).

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The navigation bar on the left side of ____ view contains commands to perform actions common to most office programs.
kondor19780726 [428]

Answer:

The navigation bar on the left side of File view  contains commands to perform actions common to most office programs.

Explanation:

It enable all kinds of operations such as opening a file, closing a file, saving the file, saving a file with a different name, listing recently opened document, etc.

The open option enable us to open an existing file, all the recent files will be listed in the recent option and there are no files opened newly or if the data are cleared often, then it will be empty.

A file can be opened and saved with the different name so that the recent change will be saved in the new file and there will be presence of existing file too.

4 0
2 years ago
A half-life is the amount of time it takes for a substance or entity to fall to half its original value. Caffeine has a half-lif
Ivan

Answer:

// program in C++.

#include <bits/stdc++.h>

using namespace std;

// main function

int main() {

 // variable

float n;  

cout<<"Enter the initial value:";

//Read the input from the user  

cin>>n;

//Declare variables for storing values at 6, 12 and 18 hours

float hours_6, hours_12, hours_18;  

//Set precision level of floating point number

cout << fixed;

    cout << setprecision(6);

 //calculate values at 6, 12 and 18 hours

hours_6 = n / 2.0;

hours_12 = hours_6 / 2.0;

hours_18 = hours_12 / 2.0;

//display the output

cout<<"After 6 hours: "<<hours_6<<"mg"<<endl;

cout<<"After 12 hours: "<<hours_12<<"mg"<<endl;

cout<<"After 18 hours: "<<hours_18<<" mg"<<endl;

return 0;

}

Explanation:

Read an input from the user. Set the precision to 6 for displaying the result up to 6 decimal places. The first half life at 6 hours can be calculated by dividing the input by 2. The half life at 12 hours can be found out by dividing the half life value at 6 hours by 2. Similarly at 18 hours, we find the half life value by dividing the half life value at 12 hours by 2.

Output:

Enter the initial value:100                                                                                                

After 6 hours: 50.000000 mg                                                                                                

After 12 hours: 25.000000 mg                                                                                              

After 18 hours: 12.500000 mg  

5 0
2 years ago
2. Because technology is always changing, there are new applications being developed constantly. (1 point)
Zepler [3.9K]
True because we need new tech
4 0
2 years ago
Read 2 more answers
Which of the following statements are true. .ascii stores string in memory and terminate it with NULL character. There is no way
Tems11 [23]

Answer:

The true statements are:

There is an assembler directive to arrange / place floating point values in static data memory

MARS always uses setting '.set boat'

Explanation:

It is the assembler directive who arranges and places the floating point values for the static data memory. Obviously there is no such way for the MIPS assemble programming for reservation of the static data memory without having any initialization for a considerable value.

MARS would definitely use the setting set “noat” ascii would store the string in the memory and then terminate it with respect to NULL character. They cannot reserve the MIPS assembly programming for a considerable value.

4 0
2 years ago
Compare the memory organization schemes of contiguous memory allocation and paging with respect to the following issues: a. Exte
Free_Kalibri [48]

Answer:

The comparison is based on memory organization schemes of contiguous memory allocation and paging with respect to External fragmentation, Internal fragmentation and Ability to share code across processes.

Explanation:

Memory organization schemes of contiguous memory allocation:

Contiguous memory allocation schemes suffers from external fragmentation. The reason is that address space is distributed contiguously and the holes and gaps keep growing when the old processes die and new processes are introduced. The variable size partition suffers from external fragmentation however the fixed size partitions do not suffer from external fragmentation. Contiguous memory allocation with variable size partitions does not encounter an internal fragmentation but with fixed size partitions suffers from internal fragmentation. Contiguous memory allocation does not support sharing code across processes. This is because the virtual memory segment of a process is not fragmented into non-contiguous fine grained blocks.

Paging:

Paging does not encounter external fragmentation as pages are of the fixed or equal size. So this reduces external fragmentation. However paging suffers from internal fragmentation. This is because a process can request more space or it can request for a less space. When page is allocated to the such a process that page is no longer utilized.This results in internal fragmentation because of the wastage of space even when the page has internal space but cannot be fully utilized. Paging allows to share code across processes.

5 0
2 years ago
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