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Artyom0805 [142]
1 year ago
10

How can a signature be added to an email message? Check all that apply.

Computers and Technology
2 answers:
worty [1.4K]1 year ago
7 0

Answer:

A C D

Explanation:

I this helped  plz sub to me on you tube at (Resurgentz)

lara [203]1 year ago
5 0

Answer: im not sure you should just you tube it

Explanation:

You tube can teach you a lot of things you just need to use it

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A(n) _____ is the highest educational degree available at a community college. master bachelor associate specialist
baherus [9]
<span>An associate's degree requires two years of academic study and is the highest degree available at a community college</span>
5 0
2 years ago
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Which of the following is a true statement about cloud computing?
Veseljchak [2.6K]

Answer:

There are additional security risks associated with using cloud computing over local data storage.                    

Explanation:

Cloud computing: The term "cloud computing" is described as a process through which an individual tends to access and store various programs and data over the internet rather than his or her computers' "hard drive". However, the term "cloud" here refers to a specific metaphor associated with the internet.

Types:

1. Software-as-a-service or SaaS.

2. Platform-as-a-service or PaaS.

3. Infrastructure-as-a-service or IaaS.

In the question above, the very first option is correct as all other options mentioned over here are incorrect because they aren't related to cloud computing.

3 0
2 years ago
Generating a signature with RSA alone on a long message would be too slow (presumably using cipher block chaining). Suppose we c
boyakko [2]

Answer:

Following are the algorithm to this question:

Explanation:

In the RSA algorithm can be defined as follows:  

In this algorithm, we select two separate prime numbers that are the "P and Q", To protection purposes, both p and q combines are supposed to become dynamically chosen but must be similar in scale but 'unique in length' so render it easier to influence. Its value can be found by the main analysis effectively.  

Computing N = PQ.  

In this, N can be used for key pair, that is public and private together as the unit and the Length was its key length, normally is spoken bits. Measure,

\lambda (N) = \ lcm( \lambda  (P), \lambda (Q)) = \ lcm(P- 1, Q - 1)  where \lambda is the total function of Carmichaels. It is a privately held value. Selecting the integer E to be relatively prime from 1and gcd(E,  \lambda (N) ) = 1; that is E \ \ and  \ \ \lambda (N).  D was its complex number equivalent to E (modulo \lambda (N) ); that is d was its design multiplicative equivalent of E-1.  

It's more evident as a fix for d provided of DE ≡ 1 (modulo \lambda (N) ).E with an automatic warning latitude or little mass of bigging contribute most frequently to 216 + 1 = 65,537 more qualified encrypted data.

In some situations it's was shown that far lower E values (such as 3) are less stable.  

E is eligible as a supporter of the public key.  

D is retained as the personal supporter of its key.  

Its digital signature was its module N and the assistance for the community (or authentication). Its secret key includes that modulus N and coded (or decoding) sponsor D, that must be kept private. P, Q, and \lambda (N) will also be confined as they can be used in measuring D. The Euler totient operates \varphi (N) = (P-1)(Q - 1) however, could even, as mentioned throughout the initial RSA paper, have been used to compute the private exponent D rather than λ(N).

It applies because \varphi (N), which can always be split into  \lambda (N), and thus any D satisfying DE ≡ 1, it can also satisfy (mod  \lambda (N)). It works because \varphi (N), will always be divided by \varphi (N),. That d issue, in this case, measurement provides a result which is larger than necessary (i.e. D >   \lambda (N) ) for time - to - time). Many RSA frameworks assume notation are generated either by methodology, however, some concepts like fips, 186-4, may demand that D<   \lambda (N). if they use a private follower D, rather than by streamlined decoding method mostly based on a china rest theorem. Every sensitive "over-sized" exponential which does not cooperate may always be reduced to a shorter corresponding exponential by modulo  \lambda (N).

As there are common threads (P− 1) and (Q – 1) which are present throughout the N-1 = PQ-1 = (P -1)(Q - 1)+ (P-1) + (Q- 1)), it's also possible, if there are any, for all the common factors (P -1) \ \ \ and \ \ (Q - 1)to become very small, if necessary.  

Indication: Its original writers of RSA articles conduct their main age range by choosing E as a modular D-reverse (module \varphi (N)) multiplying. Because a low value (e.g. 65,537) is beneficial for E to improve the testing purpose, existing RSA implementation, such as PKCS#1, rather use E and compute D.

8 0
2 years ago
A customer states that when she removes the printed pages from her laser printer output tray, the black ink smears all over her
luda_lava [24]

Answer:

B. Fuser unit

Explanation:

Based on the scenario that is being described it can be said that the most likely problem is the Fuser unit. This is a part that plays an important role in the printing process. This unit melts the toner and compresses it in order to leave the impression on the paper with heat. A faulty fuser unit will not compress correctly and leave wet ink on the paper causing it to smear.

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Each level of a smartphone app adds more gems for you to match. On level one, there were 13 gems. On level twelve, there were 12
Sidana [21]
<span>Level : 1,2,3,4,5,6,7,8,9,10,11,12
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We have to increase from 13 to 123 over a span of 11 levels.
That's an increase of 110 over 11 levels.
110 / 11 = 10
So we go up 10 gems each level Level : 1,2,3,4,5,6,7,8,9,10,11,12
Gems : 13 23 33 43 53 63 73 83 93 103 113 123</span>
5 0
2 years ago
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