How can a signature be added to an email message? Check all that apply.

The compare_strings function is supposed to compare just the alphanumeric content of two strings, ignoring upper vs lower case a

Korolek [52]

Answer:

There is a problem in the given code in the following statement:

Problem:

punctuation = r"[.?!,;:-']"

This produces the following error:

Error:

bad character range

Fix:

The hyphen - should be placed at the start or end of punctuation characters. Here the role of hyphen is to determine the range of characters. Another way is to escape the hyphen - using using backslash \ symbol.

So the above statement becomes:

punctuation = r"[-.?!,;:']"

You can also do this:

punctuation = r"[.?!,;:'-]"

You can also change this statement as:

punctuation = r"[.?!,;:\-']"

Explanation:

The complete program is as follows. I have added a print statement print('string1:',string1,'\nstring2:',string2) that prints the string1 and string2 followed by return string1 == string2 which either returns true or false. However you can omit this print('string1:',string1,'\nstring2:',string2) statement and the output will just display either true or false

import re #to use regular expressions

def compare_strings(string1, string2): #function compare_strings that takes two strings as argument and compares them

string1 = string1.lower().strip() # converts the string1 characters to lowercase using lower() method and removes trailing blanks

string2 = string2.lower().strip() # converts the string1 characters to lowercase using lower() method and removes trailing blanks

punctuation = r"[-.?!,;:']" #regular expression for punctuation characters

string1 = re.sub(punctuation, r"", string1) # specifies RE pattern i.e. punctuation in the 1st argument, new string r in 2nd argument, and a string to be handle i.e. string1 in the 3rd argument

string2 = re.sub(punctuation, r"", string2) # same as above statement but works on string2 as 3rd argument

print('string1:',string1,'\nstring2:',string2) #prints both the strings separated with a new line

return string1 == string2 # compares strings and returns true if they matched else false

#function calls to test the working of the above function compare_strings

print(compare_strings("Have a Great Day!","Have a great day?")) # True

print(compare_strings("It's raining again.","its raining, again")) # True

print(compare_strings("Learn to count: 1, 2, 3.","Learn to count: one, two, three.")) # False

print(compare_strings("They found some body.","They found somebody.")) # False

The screenshot of the program along with its output is attached.

4 0

2 years ago

Nstructions

Degger [83]

Answer:

the answer is yes

Explanation:

7 0

2 years ago

1. Assign to maxSum the max of (numA, numB) PLUS the max of (numY, numZ). Use just one statement. Hint: Call FindMax() twice in

Roman55 [17]

Answer:

1)

maxSum = FindMax(numA, numB) + FindMax(numY, numZ);

2)

void PrintFeetInchShort(int numFeet , int numInches){

cout<<numFeet<<"'"<<numInches<<"\""; }

3)

void PrintTicTacToe(char horizChar, char vertChar){

for(int r=1;r<=3;r++) {

for(int c=1;c<=3;c++) {

cout<<"x";

if(c<=2) {

cout<<vertChar; } }

cout<<endl;

if(r != 3) {

for(int c = 1; c<=5; c++) {

cout<<horizChar; }

cout<<endl; } } }

4)

void PrintShape(){

for(int r=1;r<=3;r++){

for(int c=1;c<=3;c++){

cout<<"*"; }

cout<<endl;} }

5)

void PrintPattern(){

for(int r=1;r<=5;r++){

cout<<"*"; } }

Explanation:

1.

In the statement, maxSum is a double type variable which is assigned the maximum of the two variables numA numB PLUS the maximum of the two variables numY numZ using which are found by calling the FindMax function. The FindMax() method is called twice in this statement one time to find the maximum of numA and numB and one time to find the maximum of numY numZ. When the FindMax() method is called by passing numA and numB as parameters to this method, then method finds if the value of numA is greater than that of numB or vice versa. When the FindMax() method is called by passing numY and numZ as parameters to this method, then method finds if the value of numY is greater than that of numZ or vice versa. The PLUS sign between the two method calls means that the resultant values returned by the FindMax() for both the calls are added and the result of addition is assigned to maxSum

2.

The above function takes two integer variables numFeet and numInches as its parameters. The cout statement is used to print the value of numFeet with a single quote at the end of that value and print the value of numInches with double quotes at the end of that value. Here \ backslash is used to use the double quotes. Backslash is used in order to include special characters in a string. In order to add double quotes with a string or a value, backslash is compulsory.

3.

The function PrintTicTacToe has two character type (char) parameters horizChar and vertChar.

The function has two loops; outer loop and an inner loop. The outer loop is used to iterate through the rows and inner loop is used to iterate through the columns. The inner loop iterates and prints a row of the character "x" followed by vertChar which contains a character ! . This means at each iteration x! is printed and it stops at the third "x" as the loop variable c iterates until the value of c remains less than or equal to 3. Notice that the last "x" in each row is not followed by a "!" because of if(c<=2) condition which prints ! only till the second column which means cout<<vertChar; statement only executes until the value of c remains less than or equal to 2. When the value exceeds 2 then the next if statement if(r != 3) executes which checks if the value of r is not equal to 3. If this condition is true then the loop inside this 2nd if statement executes which prints value of horizChar at each iteration and horizChar contains "~". c<=5; means that the loop will print "~" 5 times. After the first row of x!x!x and ~~~~~ are printed the outer loop executes for the next iteration and outer loop variable r is incremented to one to print the second row of x!x!x

~~~~~ using inner loop and two if conditions. This outer loop body executes 3 times.

4.

The function has two loops an inner and outer loop. Outer loop is used for rows and inner for columns. At each iteration of inner loop an asterisk is printed and the inner loop runs for 3 times which means three asterisks will print ***. The outer loop executes for 3 times which means total three rows of three *** asterisks are displayed each *** asterisks are printed with a new line using cout<<endl; statement.

5.

The function uses a loop for(int r=1;r<=5;r++) to print 5 asterisks ***** without printing a new line. The function PrintPattern() is called twice which means the pattern of 5 asterisks ***** is printed twice as: ********** without printing a new line between them.

3 0

2 years ago

Identify the tips to create a well-designed digital portfolio.

Levart [38]

Answer:

B. She created a person website with a unique URL for her online portfolio

Explanation:

8 0

2 years ago

During a traceroute, which action does a router perform to the value in the Time To Live (TTL) field?

Sladkaya [172]

Answer:

<em>During a traceroute, the router decreases the Time To Live values of the packet sent from the traceroute by one during routing, discards the packets whose Time To Live values have reached zero, returning the ICMP error message ICMP time exceeded.</em>

Explanation:

Traceroute performs a route tracing function in a network. It is a network diagnostic commands that shows the path followed, and measures the transit delays of packets across an Internet Protocol (IP) network, from the source to the destination, and also reports the IP address of all the routers it pinged along its path. During this process, the traceroute sends packets with Time To Live values that increases steadily from packet to packet; the process is started with Time To Live value of one. <em>At the routers, the Time To Live values of the packets is gradually decreased by one during routing, and the packets whose Time To Live values have reached zero are discarded, returning the ICMP error message ICMP Time Exceeded</em>

7 0

2 years ago