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Semenov [28]
2 years ago
7

Write a static generic method PairUtil.minmax that computes the minimum and maximum elements of an array of type T and returns a

pair containing the minimum and maximum value. Require that the array elements implement the Measurable interface of Section 10.1.2.
Computers and Technology
1 answer:
Gnesinka [82]2 years ago
5 0

Answer:

Explanation:

The following code is written in Java. It is hard to fully create the code without the rest of the needed code including the T class and the Measurable interface. Regardless the following code can be implemented if you have that code available.

 public static T minmax(ArrayList<T> mylist) {

       T min = new T();

       T max = new T();

       for (int x = 0; x < mylist.size(); x++) {

           if (mylist.get(x) > max) {

               max = mylist.get(x);

           } else if (mylist.get(x) < min) {

               min = mylist.get(x);

           }

       }

       

       return (min, max);

   }

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The answer & explanation for this question is given in the attachment below.

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Problem 1a. Write a function named hasFinalLetter that takes two parameters 1. strList, a list of non-empty strings 2. letters,
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Answer:

The answer is the programming in Python language has strings and characters that has to be declared in the method.

Explanation:

#method

def hasFinalLetter(strList,letters):

output = #output list

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for string in strList:

#findout the length of each string in strList

length = len(string)

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#TestCase 1 that will lead to return empty list

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print hasFinalLetter(strList1,letters1)

#TestCse2

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print hasFinalLetter(strList2,letters2)

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Option D

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The code selection above is taken from the Color Sleuth activity you just completed. This selection would count as an abstractio
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Input a number [1-50] representing the size of the shape and then a character [x,b,f] which represents the shape i.e. x-&gt;cros
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Answer:

C++ code given below with appropriate comments

Explanation:

pattern.cpp

#include<iostream>

using namespace std;

void printCross(int n)

{

int i,j,k;

if(n%2) //odd number of lines

{

for(int i=n;i>=1;i--)

{

for(int j=n;j>=1;j--)

{

if(j==i || j==(n-i+1))

cout<<j;

else

cout<<" ";

}

cout<<"\n";

}

}

else //even number of lines

{

for(int i=1;i<=n;i++)

{

for(int j=1;j<=n;j++)

{

if(j==i || j==(n-i+1))

{

cout<<" "<<j<<" ";

}

else

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}

cout<<"\n";

}

}

}

void printForwardSlash(int n)

{

if(n%2)

{

for(int i=n;i>=1;i--)

{

for(int j=n;j>=1;j--)

{

if(j==n-i+1)

{

cout<<j;

}

else

cout<<" ";

}

cout<<"\n";

}

}

else

{

for(int i=1;i<=n;i++)

{

for(int j=1;j<=n;j++)

{

if(j==(n-i+1))

{

cout<<j;

}

else

cout<<" ";

}

cout<<"\n";

}

}

}

void printBackwardSlash(int n)

{

if(n%2) // odd number of lines

{

for(int i=n;i>=1;i--)

{

for(int j=n;j>=1;j--)

{

if(j==i)

{

cout<<j;

}

else

cout<<" ";

}

cout<<"\n";

}

}

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{

for(int i=1;i<=n;i++)

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for(int j=1;j<=n;j++)

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if(j==i)

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cout<<j;

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int main()

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int num;

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cin>>num>>ch;

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printForwardSlash(num);

else if(ch=='b' || ch=='B')

printBackwardSlash(num);

else

cout<<"\nWrong input"<<endl;

return 0;

}

4 0
2 years ago
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